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NARA [144]
3 years ago
5

Which unit of a measurement is better for determining the volume for a drop of water. A milliliter, or a liter?

Physics
1 answer:
IceJOKER [234]3 years ago
6 0
A milliliter, because it is a smaller unit of measurement more fitting for a drop of water.
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A ball is thrown horizontally from the top of a tall cliff. Neglecting air drag, what vertical distance will the ball have falle
adell [148]

The relevant equation to use here is:

y = v0 t + 0.5 g t^2

where y is the vertical distance, v0 is initial velocity = 0, t is time, g = 9.8 m/s^2

 

y = 0 + 0.5 * 9.8 * 3^2

<span>y = 44.1 meters</span>

5 0
4 years ago
The most important part of physical fitness is. Strength. B muscular endurance c flexibility. D. Cardiovascular
solniwko [45]
The answer is D. Cardiovascular
7 0
3 years ago
According to Newton's first Law of motion, it takes forces to be balanced to move an object from its resting position.
Snowcat [4.5K]
False. First Law of Newton states that object tends to be at rest until an external force is applied and vice-versa. 
4 0
3 years ago
Read 2 more answers
How many photons strike the cd surface during the playing of a cd 69 minutes in length?
Reptile [31]

Answer:

Photons strike the CD n=1.624 x10^{18}

Explanation:

First of all, it is necessary to calculate the energy produced by a semiconductor laser for 69 minutes:

69minutes*\frac{60s}{1 minute}=4140s

E=0.1x10^{-3}w*4140s=0.414J

Next, it is possible to calculate the number of photons striking the CD surface during this time:

E=\frac{n*h*c}{l}

l=780x10^{-9}m long in CD

c=3x10^8 m/s light velocity

h=6.626x10^{-34} J*s

Solve to n'

n=\frac{E*l}{c*h}=\frac{0.414 J*780x10^{-9}m}{3x10^8m/s*6.626x10^{-34}}

n=1.624 x10^{18}

8 0
3 years ago
A 120 Ω resistor, a 60 Ω resistor, and a 40 Ω resistor are connected in parallel and placed across a potential difference of 12.
Westkost [7]

Answer:

The equivalent resistance of the parallel circuit would be 20 Ω

Explanation:

To calculate the resistance of resistors connected in parallel, the formula to be used is

1/R = 1/R₁ + R₂ + R₃ + R₄...

1/R = 1/120 + 1/60 + 1/40

1/R = (1 + 2 + 3)/120

1/R = 6/120

1/R = 1/20 Ω

This can be rewritten or cross-multiplied to be

R × 1 = 20 × 1

R = 20 Ω

The equivalent resistance (R) would then be 20 Ω

7 0
3 years ago
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