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iren [92.7K]
3 years ago
11

What is the sum? 8+(-12) О-20 0-4 020

Mathematics
2 answers:
rodikova [14]3 years ago
7 0

Answer: -4

Work: So, to get -4, we need to simplify the equation. If you see any equation with +(- that's subtraction. So, with the rule, this equation is basically 8-12, and that's -4.

skad [1K]3 years ago
3 0

Answer:

-4

Step-by-step explanation:

8+(-12)

= 8-12

12-8=4

the answer is -4

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If a+b=9 and ab=18,find the value of a and b.
Blizzard [7]

Answer:

Given:

a + b = 9

=> a = 9 - b

Given:

a x b = 18

=> (9 - b) x b = 18

=> 9b - b^2 = 18

=> b^2 - 9b + 18 = 0

=> (b - 3)(b - 6) = 0

=> b = 3 => a = 6

=> b = 6 => a = 3

Hope this helps

:)

3 0
3 years ago
Write the expression for the Area of the polygon BORT MO 6 A= O A = 6m + mp O A = mp + 1/2(6m) O A = mp + 6p
anyanavicka [17]

We are asked to determine the area of the given figure. To do that we will divide the figure into a square and a triangle. The area of the square is the product of its dimension, therefore, the area is:

A_{sq}=mp

The area of the triangle is given by the following formula:

A_t=\frac{bh}{2}

Where "b" is the base and "h" is its height. Replacing the values:

A_t=\frac{(6)(m)}{2}=\frac{1}{2}6m

The total area is the sum of both areas:

A=A_{sq}+A_t

replacing the areas:

A=mp+\frac{1}{2}6m

7 0
1 year ago
Factor each completely<br><br> n^2 - 11n + 10
Charra [1.4K]

{n}^{2}  - 11n + 10 =

(n - 1)(n - 10)

.................................................

3 0
2 years ago
How do you write 3.50 x 102 in standard form?
vekshin1
357 is your answer because all you do is solve the problem =
6 0
3 years ago
Sea un cuadrado de 2 pulgadas de lado uniendo los puntos medios se obtiene otro cuadrado inscrito en el anterior si repetimos es
Ne4ueva [31]

Answer:

1) La serie geométrica formada es

4, 2, 1,..., ∞

2) La suma al infinito de las áreas de los cuadrados es 8 in.²

Step-by-step explanation:

1) El área del primer cuadrado, a₁ = 2² = 4 pulgadas²

El área del siguiente cuadrado, a₂ = (√ (1² + 1²)) ² = (√2) ² = 2 pulg²

El área del siguiente cuadrado, a₃ = ((√ (2) / 2) ² + (√ (2) / 2) ²) = 1 pulg²

Por lo tanto, la razón común, r = a₂ / a₁ = 2/4 = a₃ / a₂ = 1/2

Las áreas de los cuadrados progresivos forman una progresión geométrica como sigue;

4, 4×(1/2), 4 ×(1/2)²,...,4×(1/2)^{\infty}

De donde obtenemos la serie geométrica formada de la siguiente manera;

4, 2, 1,..., ∞

2) La suma de 'n' términos de una progresión geométrica hasta el infinito para -1 <r <1 se da como sigue;

S_{\infty} = \dfrac{a}{1 - r}

Por lo tanto, la suma de las áreas de los cuadrados hasta el infinito se obtiene sustituyendo los valores de 'a' y 'r' en la ecuación anterior de la siguiente manera;

La \ suma \ al \ infinito \ del \ cuadrado \ S_{\infty}  = \dfrac{4 \ in.^2}{1 - \dfrac{1}{2} } = \dfrac{4 \ in.^2}{\left(\dfrac{1}{2} \right)} = 2 \times 4 \ in.^2= 8 \ in.^2

La suma al infinito de las áreas de los cuadrados, S_{\infty} = 8 in.²

7 0
3 years ago
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