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3 years ago

What is the sum? 8+(-12) О-20 0-4 020

Mathematics

2 answers:

rodikova [14]3 years ago

7 0

Answer: -4

Work: So, to get -4, we need to simplify the equation. If you see any equation with +(- that's subtraction. So, with the rule, this equation is basically 8-12, and that's -4.

skad [1K]3 years ago

3 0

Answer:

-4

Step-by-step explanation:

8+(-12)

= 8-12

12-8=4

the answer is -4

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Kong took 15% fewer seconds than Nolan took to complete his multiplication timed test. Kong took 85 seconds. How many seconds di

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85 + 12.75 = 97.75
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2 years ago

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A product is made up of components A, B, C, D, E, F, G, H, I, and J. Components A, B, C, and F have a 1/10,000 chance of failure

Svetach [21]

Answer:

The overall reliability is 99.7402 %

Step-by-step explanation:

The overall reliability of the product is calculated as the product of the working probability of the components.

For components A,B,C and F we have :

$P(failure)=\frac{1}{10000}$

⇒

$P(Work)=1-\frac{1}{10000}=\frac{9999}{10000}=0.9999$

For components D,E,G and H we have :

$P(failure)=\frac{3}{10000}$

⇒

$P(Work)=1-\frac{3}{10000}=\frac{9997}{10000}=0.9997$

Finally, for components I and J :

$P(failure)=\frac{5}{10000}$

⇒

$P(Work)=1-\frac{5}{10000}=\frac{9995}{10000}=0.9995$

Now we multiply all the working probabilities. We mustn't forget that we have got ten components in this case :

Components A,B,C and F with a working probability of 0.9999

Components D,E,G and H with a working probability of 0.9997

Components I and J with a working probability of 0.9995

Overall reliability = $(0.9999)^{4}(0.9997)^{4}(0.9995)^{2}=0.997402$

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3 years ago

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Answer:

First equation = 3a + 9

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Second equation = a²- 9

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Hence,

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Hope this helped

All the best !!

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tensa zangetsu [6.8K]

Answer:

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