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kobusy [5.1K]
3 years ago
10

Simplify $\frac{-10a^2b^4}{5a^{-9}b^{-5}}$

Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
5 0
\bf ~~~~~~~~~~~~\textit{negative exponents}
\\\\
a^{-n} \implies \cfrac{1}{a^n}
\qquad \qquad
\cfrac{1}{a^n}\implies a^{-n}
\qquad \qquad 
a^n\implies \cfrac{1}{a^{-n}}
\\\\
-------------------------------\\\\
\cfrac{-10a^2b^4}{5a^{-9}b^{-5}}\implies \cfrac{-10}{5}\cdot \cfrac{a^2b^4}{a^{-9}b^{-5}}\implies \cfrac{-2}{1}\cdot \cfrac{a^2a^9b^4b^5}{1}
\\\\\\
-2a^{2+9}b^{4+5}\implies -2a^{11}b^9
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Graph the first six terms of a sequence where a1 = 3 and d = −10.
Aleks [24]

Answer:

Step-by-step explanation:

nth term = (n-1)th term + common difference

d = -10

a₁ = 3

a₂ = a₁ + d = 3 + (-10) = -7

a₃ = a₂ + d = -7 + (-10) = -17

a₄ = a₃ + d = -17 + (-10) = -27

a₅ =a₄ + d = -27 + (-10) = -37

a₆ = a₅ + d = -37 + (-10) = -47

First six terms: 3 , -7 , -17, -27, -37 , -47

7 0
3 years ago
What is the value of x in the equation 1.5(x + 4) – 3 = 4.5(x – 2)?
Pepsi [2]
X=4
Step 1: Simplify both sides of the equation.
1.5(x+4)-3=4.5(x-2)
(1.5)(x)+(1.5)(4)+ -3 =(4.5)(x)+(4.5)(-2)
(1.5x) + ( 6+-3) =4.5x - 9
(Combine like terms)
1.5x+3=4.5x-9

Step 2: Subtract 4.5x from both sides.
1.5x +3 -4.5x =4.5x=-9-4.5x-3x+3=-9

Step 3: Subtract 3 from both sides.
-3x+3-3=-9-3
-3x=12

Step 4: Divide both by -3
-3x/-3=-12/-3
X=4
6 0
3 years ago
Please explain how to do and set up
In-s [12.5K]

A

using the Cosine rule in ΔSTU

let t = SU, s = TU and u = ST, then

t² = u² + s² - (2us cos T )

substitute the appropriate values into the formula

t² = 5² + 9² - (2 × 5 × 9 × cos68° )

   = 25 + 81 - 90cos68°

   = 106 - 33.71 = 72.29

⇒ t = \sqrt{72.29} ≈ 8.5 in → A


6 0
3 years ago
Please help explain how to solve problem 16?
Anarel [89]
Here is the problem.....√(15x + 10) = 2x+3

to remove the square root, we do the opposite which is to square everything.

(√(15x + 10))² = (2x + 3)²      (the square negates the square root)
15x + 10 = (2x +3)(2x + 3)    (use the distributive property to continue)
15x + 10 = 4x² + 6x + 6x + 9  (combine like terms)
15x + 10 = 4x² + 12x + 9      (subtract 15x and 10 from each side)
-15x - 10          -15x - 10
0 = 4x² - 3x - 1                      (factor completely)
(x - 1) (4x + 1)                    (set each to equal 0)

x - 1 = 0                4x + 1 = 0
x = 1                      4x = -1
                               x = -1/4

place both into the equation to check for reasonableness...we see the negative number is not reasonable, but the x value of 1 is a solution.

answer is 1
4 0
3 years ago
If the radius is 18 cm and the angle at centre of circle is 120° then the
PolarNik [594]

The area of a sector is 339.336 cm²

The area of a sector is defined to be as the region of space bounded by a boundary from the center of the circle.

It can be determined by using the formula:

\mathbf{A = \dfrac{\theta }{360}\times \pi r^2 }

Given that;

  • Radius r = 18 cm
  • Angle θ =  120°

Then. the area of the sector can be calculated as:

\mathbf{A = \dfrac{120}{360}\times \pi (18)^2 }

\mathbf{A = \dfrac{1}{3}\times 3.142 \times 324 }

A = 339.336 cm²

Learn more about the area of a sector here:

brainly.com/question/7512468?referrer=searchResults

4 0
2 years ago
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