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kobusy [5.1K]
3 years ago
10

Simplify $\frac{-10a^2b^4}{5a^{-9}b^{-5}}$

Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
5 0
\bf ~~~~~~~~~~~~\textit{negative exponents}
\\\\
a^{-n} \implies \cfrac{1}{a^n}
\qquad \qquad
\cfrac{1}{a^n}\implies a^{-n}
\qquad \qquad 
a^n\implies \cfrac{1}{a^{-n}}
\\\\
-------------------------------\\\\
\cfrac{-10a^2b^4}{5a^{-9}b^{-5}}\implies \cfrac{-10}{5}\cdot \cfrac{a^2b^4}{a^{-9}b^{-5}}\implies \cfrac{-2}{1}\cdot \cfrac{a^2a^9b^4b^5}{1}
\\\\\\
-2a^{2+9}b^{4+5}\implies -2a^{11}b^9
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<u>The correct answer is B. Accounts payable for US$ 53.oo</u>

Step-by-step explanation:

1. Let's recall what is the Journal entry when a company return part of the inventory previously purchased:

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The amount Heidi's accessories owed to the supplier would have been sitting as a credit on the accounts payable account because the invoice has not been payed. In the case of this return, we should debit it because we should diminish the amount due.

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The goods Heidi's accessories are returning and therefore, the asset of inventory decreases. The credit to purchase returns reduces the value of the total purchases. That's why options C and D are incorrect.

2. Now, let's calculate the amount of the return that Heidi's accessories made, this way:

Return = Number of necklaces * Price of each necklace + Sales taxes

Replacing with the real values, we have:

Return = 5 * 10 + (5 * 10) * 0.06

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Answer:

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