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Natali5045456 [20]
3 years ago
6

Pb(NO3)2+K2CrO4 --> PbCrO4+KNO3 How do you balance this?

Chemistry
1 answer:
belka [17]3 years ago
5 0

Answer:

Pb(NO₃)₂ + K₂CrO₄ ⟶ PbCrO₄ + 2KNO₃

Step-by-step explanation:

The unbalanced equation is

Pb(NO₃)₂ + K₂CrO₄ ⟶ PbCrO₄ + KNO₃

Notice that the complex groups like NO₃ and CrO₄ stay the same on each side of the equation.

One way to simplify the balancing is to replace them with a single letter.

(a) For example, let <em>X = NO₃</em> and <em>Y =CrO₄</em>. Then, the equation becomes

PbX₂ + K₂Y ⟶ PbY + KX

(b) You need 2X on the right, so put a 2 in front of KX.

PbX₂ + K₂Y ⟶ PbY + 2KX

(c) Everything is balanced. Now, replace X and Y with their original meanings.  The balanced equation is

Pb(NO₃)₂ + K₂CrO₄ ⟶ PbCrO₄ + 2KNO₃

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B) Cesium: 1s² 2s²2p⁶ 3s²3p⁶ 3d¹⁰ 4s² 4p⁶ 4d¹⁰ 5s² 5p⁶ 6s¹

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Answer:

The answer to your question is below

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