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-Dominant- [34]
3 years ago
6

Explain in detail what causes tides and give one reason why it is important for humans to monitor tides.

Physics
2 answers:
Softa [21]3 years ago
7 0

Wishy washy is correct she helps :)

Klio2033 [76]3 years ago
3 0
The gravitational attraction to the moon causes the Earth's oceans to bulge out in the direction of the moon. Another bulge occurs on the opposite side, since the Earth itself is pulled towards the moon (and away from the water on the far side). Since the Earth rotates, this happens twice a day. These are tides.

As for the importance of monitoring tides, one reason is that commercial and recreational fishermen use their knowledge of the tides and tidal currents to help them improve their catches. Monitoring the tides is a very important part of their livelihood.
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A group of particles is traveling in a magnetic field of unknown magnitude and direction. You observe that a proton moving at 1.
Brilliant_brown [7]

Answer:

Explanation:

velocity of proton  v = 1.5 x 10³ i  m /s

charge on proton e = 1.6 x 10⁻¹⁹ C

Let the magnetic field be B = Bx i + Bz k

force on charged particle ( proton )

F = e ( v x B )

2.06  x10⁻¹⁶ j = 1.6 x 10⁻¹⁹ [ 1.5 x 10³ i x ( Bx i + Bz k) ]

2.06  x10⁻¹⁶ j = - 1.6 x 10⁻¹⁹ x 1.5 x 10³  Bz j) ]

2.06  x10⁻¹⁶ = - 1.6 x 10⁻¹⁹ x 1.5 x 10³  Bz

Bz = -  .8583  

force on charged particle ( electron )

F = e ( v x B )

8.40  x10⁻¹⁶ j = -1.6 x 10⁻¹⁹ [ - 4.4 x 10³ k  x ( Bx i + Bz k) ]

8.4  x10⁻¹⁶ j =  1.6 x 10⁻¹⁹ x 4.4 x 10³  Bx j ]

- 8.4  x10⁻¹⁶ =  1.6 x 10⁻¹⁹ x 4.4 x 10³  Bx

Bx =  - 1.19

Magnetic field = - 1.19 i - .8583 k

magnitude = √ (1.19² + .8583²)

= 1.467 T

If it is making angle θ with x - axis in x -z plane

Tanθ = (.8583 / 1.19 )

36⁰ .

C )

v = - 3.7 x 10³j m /s

e = - 1.6 x 10⁻¹⁶ C

Force = F = e ( v x B )

= -1.6 x 10⁻¹⁹ [ -3.7 x 10³ j  x ( Bx i + Bz k) ]

=  - 1.6 x 10⁻¹⁹ x 3.7 x 10³  Bx  k -1.6 x 10⁻¹⁹ x 3.7 x 10³Bzi ]

=    5.08 i - 7.04 k

Tanθ = 54 ° .

5 0
3 years ago
Please Help me to find the answer...​
KonstantinChe [14]

Answer:

1. S-S Repulsion           N-S Attraction

2. S-N Attraction          N-N Repulsion

Explanation:

1. S-S Repulsion           N-S Attraction

2. S-N Attraction          N-N Repulsion

3 0
2 years ago
A flying saucer moving initially at 20 m/s[E] accelerates to 50 m/s[W] in 3.8 s. Find the saucer's average
Rashid [163]

Answer:A flying saucer moving initially at 20 m/s[E] accelerates to 50 m/s[W] in 3.8 s. Find the saucer's average

acceleration during the time interval.

22. Two arrows are launched at the same time with the same speed of 10 m/s. Arrow A is launched at an angle of 65 degrees, and arrow B at an angle of 25 degrees. Both land at the same spot on the horizontal ground. Ignore air resistance and the height of the archet How long does it take for both arrows to land on the ground?

*Our experts’ time to respond varies by subject and question (we average 46 mins)

**Content not available for all Textbook Solutions or subjects

Explanation:

8 0
2 years ago
1. What do you notice from the picture?<br>2. Did anyone get the correct answer? ​
Fudgin [204]

Answer:

1. I notice nothing because is no picture it probably didnt work

2. idk

6 0
3 years ago
Carbon-14 is used to determine the time an organism was living. The amount of carbon-14 an organism has is constant with the atm
lutik1710 [3]

Answer:

The age of the organism is approximately 11460 years.

Explanation:

The amount of carbon-14 decays exponentially in time and is defined by the following equation:

\frac{n(t)}{n_{o}} = e^{-\frac{t}{\tau} } (1)

Where:

n_{o} - Initial amount of carbon-14.

n(t) - Current amount of carbon-14.

t - Time, measured in years.

\tau - Time constant, measured in years.

Then, we clear the time within the formula:

t = -\tau \cdot \ln \frac{n(t)}{n_{o}} (2)

In addition, time constant can be calculated by means of half-life of carbon-14 (t_{1/2}), measured in years:

\tau = \frac{t_{1/2}}{\ln 2}

If we know that \frac{n(t)}{n_{o}} = 0.25 and t_{1/2} = 5730\,yr, then the age of the organism is:

\tau = \frac{5730\,yr}{\ln 2}

\tau \approx 8266.643\,yr

t = -(8266.643\,yr)\cdot \ln 0.25

t \approx 11460.001\,yr

The age of the organism is approximately 11460 years.

8 0
3 years ago
Read 2 more answers
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