Coulomb's law states<span> that: The magnitude of the electrostatic force of interaction between two point charges is directly proportional to the scalar multiplication of the magnitudes of charges and inversely proportional to the square of the distance between them.
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Answer:
the unit of work is derived unit because joule is defined the work done by the force aftab 1 newton causing the displacement of one metre something newton metre(n-m) is also used to measuring work.
D. White is a reflectiom of all colors
Answer:
a) 0.0288 grams
b) ![2.6*10^{-10} J/kg](https://tex.z-dn.net/?f=2.6%2A10%5E%7B-10%7D%20J%2Fkg)
Explanation:
Given that:
A typical human body contains about 3.0 grams of Potassium per kilogram of body mass
The abundance for the three isotopes are:
Potassium-39, Potassium-40, and Potassium-41 with abundances are 93.26%, 0.012% and 6.728% respectively.
a)
Thus; a person with a mass of 80 kg will posses = 80 × 3 = 240 grams of potassium.
However, the amount of potassium that is present in such person is :
0.012% × 240 grams
= 0.012/100 × 240 grams
= 0.0288 grams
b)
the effective dose (in Sieverts) per year due to Potassium-40 in an 80- kg body is calculate as follows:
First the Dose in (Gy) = ![\frac{energy \ absorbed }{mass \ of \ the \ body}](https://tex.z-dn.net/?f=%5Cfrac%7Benergy%20%5C%20absorbed%20%7D%7Bmass%20%5C%20of%20%5C%20the%20%5C%20body%7D)
= ![\frac{1.10*10^6*1.6*10^{-14}}{80}](https://tex.z-dn.net/?f=%5Cfrac%7B1.10%2A10%5E6%2A1.6%2A10%5E%7B-14%7D%7D%7B80%7D)
= ![2.2*10^{-10} \ J/kg](https://tex.z-dn.net/?f=2.2%2A10%5E%7B-10%7D%20%5C%20J%2Fkg)
Effective dose (Sv) = RBE × Dose in Gy
Effective dose (Sv) = ![1.2 *2.2*10^{-10} \ J/kg](https://tex.z-dn.net/?f=1.2%20%20%2A2.2%2A10%5E%7B-10%7D%20%5C%20J%2Fkg)
Effective dose (Sv) = ![2.6*10^{-10} J/kg](https://tex.z-dn.net/?f=2.6%2A10%5E%7B-10%7D%20J%2Fkg)