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3 years ago

Where is there potential energy throughout the loading, cocking, and releasing if the trebuchet?

Physics

1 answer:

pshichka [43]3 years ago

4 0

Answer:

adapted from NOVA, a team of historians, engineers, and trade experts recreate a medieval throwing machine called a trebuchet. To launch a projectile, a trebuchet utilizes the transfer of gravitational potential energy into kinetic energy. A massive counterweight at one end of a lever falls because of gravity, causing the other end of the lever to rise and release a projectile from a sling. As part of their design process, the engineers use models to help evaluate how well their designs will work.

Explanation:

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katen-ka-za [31]

Mg + 2HCl —> MgCl2 + H2

6 0

3 years ago

One liter of water at 56◦C is used to make iced

Genrish500 [490]

Answer:22.6g

Explanation:

Mass of water(mw)=1liter=1000g

Final temperature=20°C

Temperature of ice=0°C

Temperature of water=56°C

Change in temperature of water=56-20=36

change in temperature of ice=20-0=20

Specific heat of water=1cal/g°C

Latent heat of ice=79.7cal/g

1000x1x36=mx79.7x20

36000=1594xm

Divide both sides by 1594

36000 ➗ 1594=1594xm ➗ 1594

22.6=m of ice

m of ice=22.6g

8 0

2 years ago

A 11kg block slides up a 30° inclined plane at a constant velocity. The coefficient of friction between the block and the plane

astra-53 [7]

Answer:

The magnitude of the applied force is 94.74 N

Explanation:

Mass of the block, m = 11 kg

Angle of inclination of the plane, $\theta = 30^{\circ}$

Friction coefficient, $\mu_{k} = 0.2$

Now,

Normal force that acts on the block is given by:

$F_{N} = mgcos\theta + Fsin\theta$ (1)

Now, to maintain the equilibrium parallel to ramp the forces must be balanced.

Thus

$Fcos\theta = \mu_{k}F_{N}$ (2)

From eqn (1) and (2)

$Fcos\theta = \mu_{k}(mgcos\theta + Fsin\theta)$

$F(cos\theta - \mu_{k}sin\theta) = \mu_{k}mgcos\theta$

$F = \frac{\mu_{k}mgcos\theta}{cos\theta - \mu_{k}sin\theta}$

$F = \frac{0.2\times 11\times 9.8cos30^{\circ}}{cos30^{\circ} - 0.2\times sin30^{\circ}}$

F = 94.74 N

3 0

3 years ago

Find the speed of a bicyclist who took an hour and a half to travel 10km

Natalija [7]

distance = 10km

time = 1 1/2 = 3/2 hours

speed = distance/time = 10 / 3/2 = 20/3 = 6.67 Km/h

7 0

2 years ago

"A proton is placed in a uniform electric field of 2750 N/C. You may want to review (Page) . For related problem-solving tips an

tekilochka [14]

To solve this problem we will start from the definition of Force, as the product between the electric field and the proton charge. Once the force is found, it will be possible to apply Newton's second law, and find the proton acceleration, knowing its mass. Finally, through the linear motion kinematic equation we will find the speed of the proton.

PART A ) For the electrostatic force we have that is equal to

$F=qE$