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3 years ago

What’s the distributive property

Mathematics

2 answers:

Inessa05 [86]3 years ago

7 0

Answer: The distributive property lets you multiply a sum by multiplying each addend separately and then add the products.

Step-by-step explanation: Hope this helps.

Komok [63]3 years ago

5 0

Answer:

According to Google, In abstract algebra and formal logic, the distributive property of binary operations generalizes the distributive law from Boolean algebra and elementary algebra. In propositional logic, distribution refers to two valid rules of replacement.

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How to simplify the square root of 126

Neporo4naja [7]

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$3 \sqrt{14}$ is the final answer :)

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3 years ago

39/250 in simplest form

OleMash [197]

Getting the simplest form of a fraction is the same with getting its lowest term. Reducing fractions to its lowest term is a very simple thing to do. Here's how to simplify fractions:

There are two ways in simplifying fractions. The first method is to equally divide both numerator and denominator which results to only whole numbers. Getting the GCF (Greatest Common Factor) or GCD (Greatest Common Divisor) is the second method.

As to the fraction above, 39/250, the second method is applicable.
Let us get the GCF of 39 and 250
39= 1,3,13,39
250= 1, 2, 5, 10, 25, 50, 125, 250

Therefore, the GCF of 39 and 250 is 1. We can conclude then that 39/250 is already on its simplest form thus;
39 ÷ 1 is equal to 39
250 1 250

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3 years ago

What equation could be used to solve for the length of XY?

Juliette [100K]

The as were is XY=22/sin(4)

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3 years ago

Read 2 more answers

The sum of the diagonals of a rhombus is 5√2.

Alex

Greetings!
Let ABCD be a rhombus
AC + BD = 5√2 cm

Area of ABCD = Ar△ABD + Ar △BCD
$= \frac{1}{2} \times BD \times AO + \frac{1}{2} \times BD \times OC$
$= \frac{1}{2} BD (AO + OC)$
$\frac{1}{2} BD \times AC$

$So, \frac{ BD \times AC}{2} = 4 \: cm {}^{2}$
$BD \times AC = 8$
$Now, AC + \: BD = 5 \sqrt{2}$

Squaring both sides, we get
$AC {}^{2} + BD {}^{2} + 2 AC.BD =50$
$AC {}^{2} + BD {}^{2} + 2 \times 8 = 50$
$AC {}^{2} + BD {}^{2} = 50 - 16$
$AC {}^{2} + BD {}^{2} = 34$

In △AOB, we have
$OA {}^{2} + OB {}^{2} =AB {}^{2}$
$( \frac{ AC }{2} ) {}^{2} + ( \frac{ BD}{2} ) {}^{2} = AB {}^{2}$
$\frac{ AC {}^{2} } {4} + \frac{ BD {}^{2} }{4} = AB {}^{2}$
$AC {}^{2} + BD {}^{2} = 4 AB {}^{2}$
$34 = 4 AB {}^{2}$

Square rooting both sides
$\sqrt{34} = 2 AB$
$Perimeter = 4 \: AB \\ = 2 \times 2 \: AB \\ = 2 \: \times \sqrt{34 } \\ = 2 \sqrt{34 \: } units$ .

Hope it helps!

7 0

3 years ago