Answer:
0
Step-by-step explanation:
f(0) = -2(0)²
= -2(0)
= 0
Answer:

Step-by-step explanation:
we are given half-life of PO-210 and the initial mass
we want to figure out the remaining mass <u>after</u><u> </u><u>4</u><u>2</u><u>0</u><u> </u><u>days</u><u> </u>
in order to solve so we can consider the half-life formula given by

where:
- f(t) is the remaining quantity of a substance after time t has elapsed.
- a is the initial quantity of this substance.
- T is the half-life
since it halves every 140 days our T is 140 and t is 420. as the initial mass of the sample is 5 our a is 5
thus substitute:

reduce fraction:

By using calculator we acquire:

hence, the remaining sample after 420 days is 0.625 kg
Triangle is equilateral with sides of 6.
Therefore all angles = 60°
Ht of 30-60-90 is 3sr3 = 5.196
Area of 30-60-90 = 1/2×b×h = 3×5.196
Area = 15.59
Pie slice from each corner = 60/360×pi×r^2, with r = 3
1/6×pi×9 = 4.71 × 3 pie slices = 14.13
So, shaded inner region = area triangle - 3 pie corners = 15.59-14.13
= 1.46
A AS
Step-by-step explanation: