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4 years ago

Gregor weighs 100 pounds. He climbs a 8 foot ladder in 10 seconds. What is Gregor's power output?

1 answer:

7 0

Given: Weight W = 100 lbs convert to Kg = 45.36 Kg

Height h = 8 Ft convert to meter = 2.44 m

Time t =10 s

Required: Power output

Formula: P = W/t Work = Force x distance or Work = mgh

P = mgh/t

P = (45.36 Kg)(9.8 m/s²)(2.44 m)/10 s

P = 108.46 J/s

P = 0.15 Horsepower

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A industrial (large) pressure cooker operates at 275 kPa. Initially there is 10 kg of water at 20Â°C, the cooker is operated unt

alex41 [277]

Answer:

$Q_{in} = 25349.92\,kJ$

Explanation:

Let establish a control volume in the industrial pressure cooker, which is a transient state system. From the First Law of Thermodynamics, the heating process is modelled:

$Q_{in} + m_{1}\cdot h_{1} - m_{2}\cdot h_{2} = (m_{1}-m_{2})\cdot u_{2} - m_{1}\cdot u_{1}$

The heat transfered to the cooker is:

$Q_{in} = m_{2}\cdot h_{2} - m_{1}\cdot h_{1} + (m_{1}-m_{2})\cdot u_{2}-m_{1}\cdot u_{1}$

Properties at each state are described below:

State 1

$u_{1} = 83.913\,\frac{kJ}{kg}$

$h_{1} = 83.915\,\frac{kJ}{kg}$

State 2

$u_{2} = 2540.1\,\frac{kJ}{kg}$

$h_{2} = 2720.9\,\frac{kJ}{kg}$

The heat transfered to the cooker is:

$Q_{in} = (9\,kg)\cdot (2720.9\,\frac{kJ}{kg} ) - (10\,kg)\cdot (83.915\,\frac{kJ}{kg} ) + (1\,kg) \cdot (2540.1\,\frac{kJ}{kg} )-(10\,kg)\cdot (83.913\,\frac{kJ}{kg} )$

$Q_{in} = 25349.92\,kJ$

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3 years ago

If a refrigerator is heat pump that follows the first law of thermodynamics, how much heat was removed from food inside of the r

aliya0001 [1]

The first law of thermodynamics is a version of the law of conservation of energy, adapted for thermodynamic systems. The law of conservation of energy states that the total energy of an isolated system is constant; energy can be transformed from one form to another, but cannot be created or destroyed. so assuming no heat losses then heat removed is also 333 J

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3 years ago

An Airbus A380 airliner can takeoff when its speed reaches 80 m/s. Suppose its engines together can produce an acceleration of 3

Tomtit [17]

Answer:

(a). The time is 26.67 sec.

(b). The distance traveled during this period is 1066.9 m.

Explanation:

Given that,

Speed = 80 m/s

Acceleration = 3 m/s

Initial velocity = 0

(a). We need to calculate the time

Using equation of motion

$v = u+at$

$t = \dfrac{v-u}{a}$

Put the value into the formula

$t = \dfrac{80-0}{3}$

$t =26.67\ sec$

The time is 26.67 sec.

(b). We need to calculate the distance traveled during this period

Using equation of motion

$s = ut+\dfrac{1}{2}at^2$

$s = 0+\dfrac{1}{2}\times3\times(26.67)^2$

$s =1066.9\ m$

The distance traveled during this period is 1066.9 m.

Hence, This is the required solution.

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3 years ago

Acetic acid (HC2H3O2) is an important ingredient of vinegar. A sample of 50.0 mL of a commercial vinegar is titrated against a 1

butalik [34]

Answer:

The concentration of acetic acid present in the vinegar is 0.113M

Explanation:

1. As the titration occurs between an acid and a base is called neutralization. The balanced chemical reaction between the acetic acid and the NaOH is:

$NaOH+HC_{2}H_{3}O_{2}=NaC_{2}H_{3}O_{2}+H_{2}O$

2. Calculate the moles of NaOH used, taking in account the concentration of NaOH 1.00M:

$5.65mL*\frac{1.00molesNaOH}{1000mLNaOH}=0.00565molesNaOH$

3. Calculate the number of moles of acetic acid neutralized using stoichiometry:

$0.00565molesNaOH*\frac{1molHC_{2}H_{3}O_{2}}{1molNaOH}=0.00565molesHC_{2}H_{3}O_{2}$

4. Calculate the concentration of acetic acid present in the vinegar:

$\frac{0.00565molesHC_{2}H_{3}O_{2}}{50.0mLvinegar}*\frac{1000mLvinegar}{1Lvinegar}=0.113M$

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3 years ago

Calculate the resultant force acting in the opposite directions:- answer asap

kap26 [50]

Answer:

Magnitude of the resultant force will be 20N in the direction of $F_2$ .

Explanation:

It's given in the question that two forces have been applied on the object given.

Since force is a vector quantity, therefore, it has magnitude and direction both.

$F_1=20N$

$F_2=40N$

Both the forces are in the opposite directions.

Therefore, magnitude of the resultant force of these forces will be,

$F_2-F_1=40-20$

= 20 N

And the direction of the resultant force will be towards $F_2$ .

Therefore, magnitude of the resultant force will be 20N in the direction of $F_2$ .

3 0

3 years ago