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2 years ago

11

A small ball with a mass of 0.6 kg and a velocity of 12 m/s hits another ball with the same mass. The firs forward and hits a th

ird ball with a mass of 0.2 kg. If the system is closed, what is the velocity of the third ball?
4 m/s

36 m/s

30 m/s

1.44 m/s

1 answer:

Ket [755]2 years ago

8 0

I think is 30m/s I am not sure

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You exert a 100-N force on a pulley system to lift 300-N. What is the mechanical advantage of this system? How many sections of

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Answer:

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Explanation:

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The mechanical advantage of the system is given by the ratio of output force to the input force.

Here, output force = 300 N and input force = 100 N

Mechanical advantage,

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Mechanical advantage is 3 it means that there are 3 sections of rope support. Hence, this is the required solution.

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A Man Moved first a Distance of 1000 m in 25 second and 2.5 km in 50 second along a in straight line?

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Answer:

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The time taken in covering next 2.5 km = 50 seconds.

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With the switch closed, how does the voltage across the 20-ω resistor compare to the voltage across the 10-ω resistor?

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In a series connection, the voltage is greater across a high-resistance resistor. Therefore, the voltage is much greater for the 20-ohm resistor. However,if it is a parallel circuit, the voltage is just the same for both resistors.

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3 years ago

A transverse wave on a string is described by the following wave function.y = (0.090 m) sin (px/11 + 4pt)(a) Determine the trans

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Explanation:

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Now, we will compare above equation with the standard form of transeverse wave equation,

y = $A sin(kx + \omega t)$

where, A is the amplitude = 0.09 m

k is the wave vector = $\frac{\pi}{11}$

$\omega$ is the angular frequency = $4\pi$

x is displacement = 1.40 m

t is the time = 0.16 s

Now, we will differentiate the equation with respect to t as follows.

The speed of the wave will be:

v(t) = $\frac{dy}{dt}$

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v(t) = -0.84 m/s

The acceleration of the particle in the location is

a(t) = $\frac{dv}{dt}$

a(t) = $-A \omega 2sin(kx + \omega t)$

a(t) = $-(0.09 m)(4 \pi)2 sin(\frac{\pi \times 1.4}{11} + 4\pi \times 0.16)$

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Hence, the value of transverse wave is 0.84 m/s and the value of acceleration is 9.49 $m/s^{2}$ .

(b) Wavelength of the wave is given as follows.

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$\lambda = (frac{2\pi}{\frac{\pi}{11})
$

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The period of the wave is

T = $\frac{2 \pi}{\omega}$

T = $\frac{2 \pi}{4 \pi}$

= 0.5 sec

Now, we will calculate the speed of propagation of wave as follows.

v = $\frac{\lambda}{T}$

= $\frac{22 m}{0.5 s}$

= 44 m/s

therefore, we can conclude that wavelength is 22 m, period is 0.5 sec, and speed of propagation of wave is 44 m/s.

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