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3 years ago

8)

Physics

1 answer:

nordsb [41]3 years ago

8 0

Answer:

Explanation:

Force of gravity isn't as strong on the moon, for example. Weight can change based on location, it is not a constant.

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Your spaceship lands on an unknown planet. To determine the characteristics of this planet, you drop a wrench from 3.00 m above

statuscvo [17]

Answer: The gravitational acceleration near the surface of this planet is 9.056 m/s^2

Explanation:

When you drop an object, the only acceleration acting on the object is the gravitational acceleration, so we can writhe the acceleration of the wrench as

a(t) = -g

where the minus sign is because the wrench will move downwards.

for the velocity of the object, we integrate over time and get:

v(t) = -g*t + v0

where v0 is the initial velocity, in this case is 0, because the wrench is droped.

integrating again, we will get the position of the wrench:

p(t) = -(g/2)*t^2 + p0

where p0 is the initial position, in this case is 3m above the ground.

p(t) = -(g/2)*t^2 + 3m

now, afther 0.814seconds the wrench hits the ground, so we have:

p(0.814 s) = 0 = -(g/2)*(0.814s)^2 + 3m

now we need to solve this for g.

-(g/2)*(0.814s)^2 + 3m = 0

(g/2)*(0.814s)^2 = 3m

(g/2) = 3m/*(0.814s)^2 = 4.528m/s^2

g = 2*4.528m/s^2 = 9.056 m/s^2

6 0

3 years ago

To drive a typical car at 40 mph on a level road for onehour requires about 3.2 × 107 J ofenergy. Suppose one tried to store thi

Ainat [17]

Answer:

$\omega=943\ rad/s$

Explanation:

Given that,

Speed of the car, v = 40 mph

Energy required, $E=3.2\times 10^7 J$

Radius of the flywheel, r = 0.6 m

Mass of flywheel, m = 400 kg

The kinetic energy of the disk is given by :

$E_k=\dfrac{1}{2}I\omega^2$

I is the moment of inertia of the disk, $I=\dfrac{mr^2}{2}$

$\omega^2=\dfrac{2E_k}{I}$

$\omega^2=\dfrac{2E_k}{\dfrac{mr^2}{2}}$

$\omega^2=\dfrac{2\times 3.2\times 10^7}{\dfrac{400\times (0.6)^2}{2}}$

$\omega=942.80\ rad/s$

$\omega=943\ rad/s$

So, the angular speed of the disk is 943 rad/s. Hence, this is the required solution.

8 0

3 years ago

Katelyn (55 kg) is practicing a drop jump in the biomechanics lab. She steps off a plyometrics box, lands on the force plate, an

suter [353]

Answer:

J = 357.5 kg*m/s

Explanation:

The impulse exerted on Katelyn when she was on the force plate, is equal to the change in her momentum, according to Newton's 2nd Law.
Assuming as the positive direction the upward direction (coincident with the positive y-axis) we can express the initial momentum as follows:

$p_{o} = m*v_{o} = 55 kg * (-3.0 m/s) (1)$