When you displace an object from its equilibrium position and the force pushing it back toward equilibrium is ____

Which fundamental force causes some forms of radioactivity? A. Gravity B. Electromagnetic force C. Strong nuclear force D. Weak

I am Lyosha [343]

Hello.

The answer is: D. weak nuclear force.

The weak force causes beta decay, a form of radioactivity. It could not be explained by the strong nuclear force, the force that’s responsible for holding the atomic nucleus together, because this force doesn’t affect electrons.

It couldn’t be the electromagnetic force, because this does not affect neutrons, and the force of gravity is far too weak to be responsible.

Have a nice day

5 0

3 years ago

A crate filled with delicious junk food rests on a horizontal floor. Only gravity and the support force of the floor act on it,

stealth61 [152]

The words "... as shown ..." tell us that there's a picture that goes along
with this question, and you decided not to share it. That's sad and
disappointing, but I think the question can be answered without seeing
the picture.

The net force on the crate is zero. Evidence for this is that fact that
the crate is just sitting there. If the net force on an object is not zero,
then the object is accelerating ... it's either speeding up, slowing down,
or its the direction of its motion is changing. If none of these things is
happening, then the net force on the object must be zero.

4 0

3 years ago

It requires 350 joules to raise a certain amount of a substance from 10.0°C to 30.0°C. The specific heat of the substance is 1.2

Akimi4 [234]

I'll assume you are looking for the mass of the object, since that is the missing piece of the puzzle.

The important equation for heat and energy is

Energy = mass × specific heat × change in temperature

Things we know:
Energy needed is 350 J.
Specific heat = 1.2 J/g°C
Temp. change = (30-20)°

Now we just need to plug those in and rearrange the formula to find the mass!

350 = mass × 1.2 × 10

6 0

4 years ago

Read 2 more answers

A 3.9 kg block is pushed along a horizontal floor by a force of magnitude 30 N at a downward angle θ = 40°. The coefficient of k

Luba_88 [7]

Answer:

The frictional force $F_{fri} =$ 6.446 N

The acceleration of the block a = 6.04 $\frac{m}{s^{2} }$

Explanation:

Mass of the block = 3.9 kg

$\theta = 40$ °

$\mu$ = 0.22

(a). The frictional force is given by

$F_{fri} = \mu R_{N}$

$R_{N} = mg \cos \theta$

$R_{N} =$ 3.9 × 9.81 × $\cos 40$

$R_{N} =$ 29.3 N

Therefore the frictional force

$F_{fri} =$ 0.22 × 29.3

$F_{fri} =$ 6.446 N

(b). Block acceleration is given by

$F_{net} = F - F_{fri}$

F = 30 N

$F_{fri}$ = 6.446 N

$F_{net}$ = 30 - 6.446

$F_{net}$ = 23.554 N

The net force acting on the block is given by

$F_{net} = ma$

23.554 = 3.9 × a

a = 6.04 $\frac{m}{s^{2} }$

This is the acceleration of the block.

8 0

3 years ago

A car will skid to halt at a uniform rate of -9.4 m/s^2. If you measure skid marks that are 34 m long, with what speed was the c

Klio2033 [76]

The speed with which the car going just before the driver slammed the brakes is 25.28 m / s, if the car skids to halt at a uniform rate of -9.4 m/s^2.

v² = u² + 2 a s

v = Final velocity

u = Initial velocity

a = Acceleration

s = Displacement

v = 0

a = - 9.4 m / s²

s = 34 m

0 = u² + ( 2 * - 9.4 * 34 )

u² = 639.2

u = 25.28 m / s

Deceleration is the slowing down of an object. It can be negative acceleration or positive acceleration. Deceleration is negative if the object moves in positive direction and it is positive if the object moves in negative direction.

Therefore, the speed with which the car going just before the driver slammed the brakes is 25.28 m / s

To know more about deceleration

brainly.com/question/17618273

#SPJ1

6 0

2 years ago

When you displace an object from its equilibrium position and the force pushing it back toward equilibrium is _____