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makvit [3.9K]
3 years ago
7

What is the y-intercept of the equation of the line that is perpendicular to the line y = 3/5x + 10 and passes through the point

(15, –5)?

Mathematics
1 answer:
melisa1 [442]3 years ago
7 0
The slope of the perpendicular line is the negative reciprocal of that of the given line, so is
  -1/(3/5) = -5/3
Then the point-slope equation of the perpendicular line can be written as
  y = (-5/3)(x -15) -5
  y = (-5/3)x +20

The y-intercept of the perpendicular line is y=20.

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