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julsineya [31]
3 years ago
6

What is the mass in grams of 14.2 liters of sulfur dioxide gas at STP?

Chemistry
1 answer:
ICE Princess25 [194]3 years ago
7 0

Answer:

Mass = 40.4 g

Explanation:

Given data:

Mass in gram = ?

Volume of SO₂ = 14.2 L

Temperature = standard = 273 K

Pressure =  standard = 1 atm

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

1 atm × 14.2 L = n × 0.0821 atm.L/ mol.K   × 273 K

14.2 atm.L = n ×  22.41 atm.L/ mol

n = 14.2 atm.L/22.41 atm.L/ mol

n = 0.63 mol

Mass of sulfur dioxide:

Mass = number of moles × molar mass

Mass = 0.63 mol × 64.1 g/mol

Mass = 40.4 g

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Water as itself can match the state of liquid, ice can match the state of a solid, and water vapor can match the state of gas.

Explanation:

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Luca wants to identify and quantity the chemicals causing air pollution in a city, but he is using a manual air sampler to colle
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Manual samplers are prone to effects of temperature, speed of wind and air concentrations.

Explanation

Manual samplers face several challenges that can act as drawbacks to obtaining accurate results. They are subjected to effects of sampling duration where long sampling times are needed to obtain adequate mass for detection. Manual samplers face challenges when measuring non-volatile species because particles are observed into the adsorption medium at a slower rate of diffusion.

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A gas effuses 4.0 times faster than oxygen (o2). what is the molecular mass of the gas? 1.0 g/mol 1.0 g/mol 2.0 g/mol 2.0 g/mol
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What do cubic measurements, live cm3, mesure?"<br> O length<br> volume
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CK-12 Boyle and Charles's Laws if Mrs. Pa pe prepares 12.8 L of laughing gas at 100.0 k Pa and -108 °C and then she force s the
nirvana33 [79]

Answer:

The answer to your question is   P2 = 2676.6 kPa

Explanation:

Data

Volume 1 = V1 = 12.8 L                        Volume 2 = V2 = 855 ml

Temperature 1 = T1 = -108°C               Temperature 2 = 22°C

Pressure 1 = P1 = 100 kPa                    Pressure 2 = P2 =  ?

Process

- To solve this problem use the Combined gas law.

                     P1V1/T1 = P2V2/T2

-Solve for P2

                     P2 = P1V1T2 / T1V2

- Convert temperature to °K

T1 = -108 + 273 = 165°K

T2 = 22 + 273 = 295°K

- Convert volume 2 to liters

                       1000 ml -------------------- 1 l

                         855 ml --------------------  x

                         x = (855 x 1) / 1000

                         x = 0.855 l

-Substitution

                    P2 = (12.8 x 100 x 295) / (165 x 0.855)

-Simplification

                    P2 = 377600 / 141.075

-Result

                   P2 = 2676.6 kPa

3 0
3 years ago
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