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saul85 [17]
3 years ago
14

A engineer measures the peak power output is 0.3227MW what is the peak power output in kilowatts ?

Chemistry
1 answer:
Lana71 [14]3 years ago
3 0
<h3>Answer:</h3>

322.7 kW

<h3>Explanation:</h3>
  • Power refers to the rate at which work is done.
  • Therefore; Power = Work done ÷ time
  • It is measured in joules per seconds or Watts

In this case, we are required to convert 0.3227 MW to kilowatts

We need to know that;

  • 10^6 watts = 1 Megawatts(MW)
  • 10^3 Watts = 1 kilowatts (kW)

Therefore;

10^3 kW = 1 MW

Therefore, the suitable conversion factor is 10^3kW/MW

Hence;

0.3227 MW is equivalent to;

   = 0.3227 MW × 10^3kW/MW

   = 322.7 kW

Thus, the peak power output is 322.7 kW

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Diffusion is a type of active transport
Rudiy27

Answer:

True

Explanation:

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3 years ago
Need help fast!!
stepan [7]

Answer:

The answer is "5.18 ".

Explanation:

It's a question of chemistry. Therefore, the following solution is provided:

We will first determine the solution's pOH. The following can possible:

The concentration of Hydroxide ion [OH^{-}] = 1.5\times 10^{-9}\ M

pOH =?\\\\pOH = -\log [OH^{-}]\\\\pOH = -\log 1.5\times 10^{-9}\\\\pOH = 8.82\\\\

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pOH = 8.82\\\\pH =?\\\\pH + pOH = 14\\\\pH + 8.82 = 14\\\\

When collecting all the like terms:

pH = 14 -8.82\\\\pH = 5.18

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3 years ago
For the reaction 2NH3(g)↽−−⇀3H2(g)+N2(g) 2 NH 3 ( g ) ↽ − − ⇀ 3 H 2 ( g ) + N 2 ( g ) the equilibrium concentrations were found
forsale [732]

Answer:

0.324

Explanation:

The following data were obtained from the question:

Concentration of NH3, [NH3] = 0.25 M

Concentration of H2, [H2] = 0.3 M

Concentration of N2, [N2] = 0.75 M

Equilibrium constant (Kc) =.?

The balanced equation for the reaction is given below:

2NH3 <==> 3H2 + N2

The equilibrium constant, Kc for a given reaction is the ratio of the concentration of the products raised to their coefficient to the concentration of the reactants raised to their coefficient. Thus, the equilibrium constant for the above reaction can be obtained as illustrated below:

Kc = [H2]³ [N2] / [NH3]²

Concentration of NH3, [NH3] = 0.25 M

Concentration of H2, [H2] = 0.3 M

Concentration of N2, [N2] = 0.75 M

Equilibrium constant (Kc) =.?

Kc = [H2]³ [N2] / [NH3]²

Kc = [0.3]³ × [0.75] / [0.25]²

Kc = (0.027 × 0.75) / 0.0625

Kc = 0.02025 / 0.0625

Kc = 0.324

Therefore, the equilibrium constant for the reaction is 0.324

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