Answer:
<em>3p + 89 < 765</em>
<em>Correct answer: D.</em>
Step-by-step explanation:
Austin, his dad, and brother make a group of three people of varying weights. Assume their average weight is p and their total weight 3p.
The cooler and other supplies weigh 89 pounds in total.
The weight of the supplies and the three people in the canoe should not be equal or exceed the maximum allowable weight of the canoe of 765 pounds.
This leads to inequality:
3p + 89 < 765
Correct answer: D.
Answer:
3.875 lb
Step-by-step explanation:
Weight of table = 19lb 4 oz = 19-4/16 lb = 19.25 lb
Weight of each chair = 11 lb 9 oz = 11-9/16 lb = 11.5625 lb
Weight of 2 chairs = 2 x 11.5625 = 23.125 lb
Difference in weight between 2 chairs and one table
= 23.125 - 19.25
= 3.875 lb
Answer:
.7
Step-by-step explanation:
30/.7 is 21
Call the number of days 'd' and the number of miles 'm'.
(Original, eh ?)
Then the equation for Gamma's price is
Price-G = 30.39d + 0.55m
and the equation for Delta's price is
Price-D = 50.31d + 0.43m .
We're going to set the prices equal, and find out
what the number of miles is:
Price-G = Price-D.
30.39d + 0.55m = 50.31d + 0.43m .
Before we go any farther, I'm going to assume that both cases would be
one-day rentals. My reasons: ==> the solution for the number of miles
depends on how many days each car was rented for; ==> even if both
cars are rented for the same number of days, the solution for the number
of miles depends on what that number of days is.
For 1-day rentals, d=1, and
30.39 + 0.55m = 50.31 + 0.43m .
Beautiful. Here we go.
Subtract 0.43m
from each side: 30.39 + 0.12m = 50.31
Subtract 30.39
from each side: 0.12m = 19.92
Divide each side by 0.12 : m = 166 .
There it is ! If a car is rented from Gamma for a day, and another car
is rented from Delta for a day, and both cars are driven 166 miles, then
the rental prices for both cars will be the same ... (namely $121.69)
0.1 = 1/10
1/10 of 1/10 is 1/100
1/100 = 0.01
0.01 is your answer
hope this helps
