Answer:
StartFraction 24 Over 65 EndFraction
Step-by-step explanation:
Total number of students = 26
Number of boys = 10
Number of girls = 26-10
=16
Eduardo has to pull two names out of the hat without replacing them.
First name
Probability= Favourable outcome/Total outcome
Probability of girls=16
Total probability=26
Eduardo has to pull two names out of the hat without replacing them.
Probability= Favourable outcome/Total outcome
=16/26
=8/13
For the second name:
Without replacement of the first hat
Probability of girls=16-1=15
Total probability=26-1=25
Probability= Favourable outcome/Total outcome
=15/25
=3/5
Probability of both of Eduardo's partner for the group project will be girls=8/13*3/5
=24/65
StartFraction 24 Over 65 EndFraction
Answer:
8 units is the answer.
Step-by-step explanation:
Pythagorean theorem can be written as,
∴ d = 8 units
For this case what we can do first is to take an average of the number of cars.
We have then:
P = (12 + 18 + 24) / (3)
P = 18
In other words, you can organize your cars in rows of 3 where each row will have 18 cars.
Answer:
three rows, 18 cars per row.
3/6 = x/7
Multiply x and 6, 3 and 7:
6x = 7*3
x = 21/6
x = 7/2
Answer. First option: t > 6.25
Solution:
Height (in feet): h=-16t^2+729
For which interval of time is h less than 104 feet above the ground?
h < 104
Replacing h for -16t^2+729
-16t^2+729 < 104
Solving for h: Subtracting 729 both sides of the inequality:
-16t^2+729-729 < 104-729
-16t^2 < -625
Multiplying the inequality by -1:
(-1)(-16t^2 < -625)
16t^2 > 625
Dividing both sides of the inequality by 16:
16t^2/16 > 625/16
t^2 > 39.0625
Replacing t^2 by [ Absolute value (t) ]^2:
[ Absolute value (t) ]^2 > 39.0625
Square root both sides of the inequality:
sqrt { [ Absolute value (t) ]^2 } > sqrt (39.0625)
Absolute value (t) > 6.25
t < -6.25 or t > 6.25, but t can not be negative, then the solution is:
t > 6.25
