While moving into a new apartment, Titus needed to hold the door open with something heavy. It suddenly dawned on him that he co
1 answer:
You might be interested in
MOHR-COULOMB FAILURE CRITERIA:
In 1900, MOHR-COULOMB states Theory of Rupture in Materials which defines as “A material fails due to because of a critical combination of normal and shear stress, not from maximum normal or shear stress”. Failure Envelope is approached by a linear relationship.
If you can not understand the below symbols see the attachment below
f f ()
Where: f = Shear Stress on Failure Plane
´= Normal Stress on Failure Plane
See the graph in the attachment
For calculating the shear stress, when Normal stress, cohesion and angle of internal friction are given. Use this formula: shear stress = f c tan
Where,
• f is Shear Stress on Failure Plane
• c is Cohesion
• is Normal Total Stress on Failure Plane
• is Friction Angle
Answer:
The correct code to this question can be de4fined as follows:
double power;
power = Math.pow(base, exp);
Explanation:
In the given question the choices were missing, that's why we defined the correct code only.
- In the given code a two double variable "base and exp" is declared, that input the value from the user-side, and store its value into there respective variables.
- In the next step, "power", that is a double variable is declared, which uses the "Math.pow" function that calculates given values power and prints its value.
please find the attachment of the full code.
