Answer:
For #5 all you have to do is set down to points in order for it to count. The answer is: (0,2) and (3,6)
Step-by-step explanation:
In order to find where exactly you must plot the points, we plug in what we know. In our equation, the 2 is our y intercept, this means that the point is (0,2) (Side Note: here's another example, (0,6) the 6 would be our y intercept)
From the point (0,2) we use the other value given. The other value given in this case, is our slope. When dealing with slope, we use Rise over Run or Rise/Run. This means that from the 2 on the graph, you rise 3 which would be 5 and you run to the right for 4. This now gets you the points (3,6)
Hope this helps with plotting the other questions! :)
(SIDE NOTE: IF THEY GIVE THE VALUE WITH X AS JUST A NUMBER, YOU CAN PLACE A 1 UNDER IT TO TURN IT INTO A FRACTION. FOR EXAMPLE 3X CAN BE TURNED INTO 3/1 WHICH WOULD THEN BE RISE 3 AND RUN 1.
(sooory about the caps, it's just to get your attention.)
It depends on what is being referred to by "this."
The description of the activity is that 10 drops are added twice and two readings are taken. If you do *that* 4 times, then a total of 20*4 = 80 drops will have been added.
If the activity referred to by "this" is the pair of acts {add 10 drops, read the volume}, then four repetitions will have added 10*4 = 40 drops.
Probably the expected interpretation is that "this" is {add 10 drops, read}, so 40 drops is likely the expected answer.
It depends what type of shape it is if it were a rectangle it would be l x w x h but what a see is a 6 sided figure so it should be a hexagon but a hexagon has all equal sides so it would depend what type of shape it is
Answer:
a) 25
b) 67
c) 97
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so 
Now, find the margin of error M as such

In which
is the standard deviation of the population and n is the size of the sample. In this problem, 
(a) The desired margin of error is $0.10.
This is n when M = 0.1. So






Rounding up to the nearest whole number, 25.
(b) The desired margin of error is $0.06.
This is n when M = 0.06. So






Rounding up, 67
(c) The desired margin of error is $0.05.
This is n when M = 0.05. So






Rounding up, 97
The answer should be C, 21. I’ll attach a picture for explanation.