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ad-work [718]
3 years ago
15

Solve the equation. t/t-8=t+8/30

Mathematics
1 answer:
sattari [20]3 years ago
4 0
<span>t/(t-8)=(t+8)/30
(t+8)(t-8) = 30t
t^2 - 8^2 = 30t
</span>t^2 - 30t - 64 = 0
<span>(t-32)(t+2) = 0
so t = 32 and t = -2
answer: 2 solutions </span>t = 32 and t = -2<span>


</span>
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consider the polynomial 2/3x (2x-3) - (x-7) (x+7) when simplified, what is the coefficent of the quadratic term?
Svet_ta [14]

Answer:

x^2 - 6x + 147 so the coefficient is 1

Step-by-step explanation:

First, simplify the equation.

1. 2/3x(2x-3) = (2x/3)(2x-3)-(x-7)(x+7)

2. 2x-3(2x/3) = (2x(2x-3)) - (x-7)(x+7)

3. Expand -(x-7)(x+7) = -x^2+49

Combine to get (x^2 - 6x)/3 +49

Simplify to get x^2 - 6x + 147. The coefficient of the quadratic term is one.

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3 years ago
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Step-by-step explanation:

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Find the range of F<img src="https://tex.z-dn.net/?f=f%28x%29%3D%20%5Cfrac%7B2%7D%7Bx-7%7D%20" id="TexFormula1" title="f(x)= \fr
steposvetlana [31]
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Well, we know there will be a horizontal asymptote at y = 0, because as x approaches infinite and negative infinite, the graph will shrink down closer and closer to 0, but never touch it. We call this a horizontal asymptote.
So we know that there is a restriction on the y-axis.

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As x  approaches the asymptote of 7⁻, then y would be diverging out to negative infinite.
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6 0
3 years ago
Please help if you can. If possible please type how you got the answer so I can remember it next time I get a question like this
Gre4nikov [31]

Answer:

(2,3)

Step-by-step explanation:

I did this by using the equation that was given. y=x+1.

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8 0
2 years ago
Read 2 more answers
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