Answer &Explanation:
From Avogadro's lawa equal volume of gas contain equal number of moles
V=N
Hence
13L=965
XL=3.2mol
Hint:as the question state is increase to iteans final mol was 3.2 but if it could state by it would mean initial moles plus adde moles ie 3.2mol)
Cross multiplication
The new volume will be
=(3.2mol×13L÷965mol)
=0.043L
Answer:
There are 6 atoms
Explanation:
2 from the subscript and multiply it by 3 cause of the coefficient.
The concentration of iron used in the titration : 0.009 M
<h3>Further explanation</h3>
Given
Reaction
Cr₂O₇²⁻ + 6Fe²⁺ + 14H⁺ ⇒ 2Cr³⁺ + 6Fe³⁺ + 7H₂O
0.0093 mol/L potassium dichromate
200 cm³ of dilute acid, 25cm³ was used in the titration.
Required
the concentration of iron
Solution
Titration formula
C₁V₁n₁=C₂V₂n₂⇒ From equation : n₁=6n₂(1=Cr₂O₇, 2=Fe)
titration average : 33+32.05+32.15+32.1 / 4 = 32.325 cm³(ml)
25 cm³ of iron solution used in titration :
Dilution(25 ml from 200 ml iron solution)
Answer: 225 joules.
Explanation:
If this a one dimension problem, this is the motion is in the same direction of the force, the equation for work is:
Work = distance × force
⇒ Work = 15 m × 15 N = 225 joules.
This is a special case of the general equation
Work = |F| |displacement| cosine (angle between the force and displacement)
When force and displacement are in the same direction, the angle is 0, so cos(0) = 1. This is the two vectors are parellel and the work is just the product of the two magnitudes (force and distance)
Answer:
Explanation:
From the equation:
H2SO4(aq) + 2NaOH(aq) --> Na2SO4(aq) + 2H2O (l)
<em>1 mole of the acid (H2SO4) and 2 moles of the base (NaOH) are required for complete neutralization.</em>
mole of acid (H2SO4) present = molarity x volume
= 1 x 0.1 = 0.1 mole
Mole of base (NaOH) present = mass/molar mass
= 7/40 = 0.175 mole
<em>The ratio of acid and base should be 1:2, hence the acid is slightly excessive in this case and the base is the limiting reagent that will determine the extent of the reaction.</em>
Amount of excess acid = 0.1 - 0.175/2
= 0.0125 mole
volume of excess acid = mole/molarity
= 0.0125 x 1 = 0.0125 L
= 12.5 mL
<em>Hence, the acid (H2SO4) was in excess by 12.5 mL.</em>
