3 years ago

What is the percent by mass of oxygen in carbon dioxide (CO2)?

Chemistry

1 answer:

Sever21 [200]3 years ago

5 0

Answer:

kkk

Explanation:

kkk

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What is the ratio? <br> A 3:1<br> B 2:1<br> C 21:7

Stolb23 [73]

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3 years ago

** worth 20 points + brainliest **

Bad White [126]

Answer : The correct option is, (D) $83^oC$

Solution :

Formula used :

$Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})$

where,

Q = heat released = -1300 J

m = mass of water = 40 g

c = specific heat of water = $4.18J/g^oC$

$\Delta T=\text{Change in temperature}$

$T_{final}$ = final temperature = ?

$T_{initial}$ = initial temperature = $91.0^oC$

Now put all the given values in the above formula, we get the final temperature of water.

$-1300J=40g\times 4.18J/g^oC\times (T_{final}-91.0^oC)$

$T_{final}=83.2^oC\approx 83^oC$

Therefore, the final temperature of the water is, $83^oC$

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3 years ago