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Alla [95]
3 years ago
5

Can somebody plz just answer this 1 question thx!!!

Chemistry
1 answer:
coldgirl [10]3 years ago
3 0

Answer:

cetacean i think thats the answer

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Calculate the ionization energy, ????????, of the one‑electron ion Be3+. The electron starts in the lowest energy level, ????=1.
spin [16.1K]

Answer:

3.49X10⁻¹⁷ J

Explanation:

The energy of an electron is given by the equation:

E = - (2.18x10^{-18})Z^2(\frac{1}{n^2})

Where Z is the number of protons of the atom and n is the energy level of the electron. For Be, Z = 4.

When n tends to infinity (1/n²) tends to 0, and at this point, the electron has left the atom, so it has ionized.

The ionization energy then is the energy of the electron that left the atom less the energy of the electron in the energy level:

I.E = - (2.18x10⁻¹⁸)x4²x0 - (-(2.18x10⁻¹⁸)x4²x(1/1²))

I.E = 3.49X10⁻¹⁷ J

3 0
3 years ago
Determine the number of moles of Mn and the number of moles of X in compound A. Clearly distinguish which is which in your calcu
KiRa [710]

Answer:

the to the same to you nd your family members for the same reason the same reason the same

5 0
3 years ago
Which of the following carbon-based molecules stores information
Eduardwww [97]

The following carbon-based molecules store information are found in living things.

All organism are made of 4 type of carbon-based= carbon hydrate, lipids, proteins, and nuclear acid

8 0
4 years ago
Complete and balance the molecular equation for the reaction of aqueous copper(II) chloride, CuCl2, and aqueous potassium phosph
aleksandrvk [35]

<u>Answer:</u> The net ionic equation is written below.

<u>Explanation:</u>

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which do not get involved in the chemical equation. It is also defined as the ions which are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of copper (II) chloride and potassium phosphate is given as:

3CuCl_2(aq.)+2K_3PO_4(aq.)\rightarrow Cu_3(PO_4)_2(s)+6KCl(aq.)

Ionic form of the above equation follows:

3Cu^{2+}(aq.)+6Cl^-(aq.)+6K^+(aq.)+2PO_4^{3-}(aq.)\rightarrow Cu_3(PO_4)_2(s)+6K^+(aq.)+6Cl^-(aq.)

As, potassium and chloride ions are present on both the sides of the reaction, thus, they will not be present in the net ionic equation.

The net ionic equation for the above reaction follows:

3Cu^{2+}(aq.)+2PO_4^{3-}(aq.)\rightarrow Cu_3(PO_4)_2(s)

Hence, the net ionic equation is given above.

7 0
3 years ago
How to solve ionic compounds
vitfil [10]

Write the symbols for the cation and the anion: Mg and Cl.

Determine the charge on the cation and anion. If the cation has a Roman numeral after it, that is the charge on that cation. ...

Determine formula.

6 0
4 years ago
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