Step 2 and all that follows is wrong because it should equal 20
Given two numbers x and y such that:
x + y = 12 ... (1)
<span>two numbers will maximize the product g</span>
from equation (1)
y = 12 - x
Using this value of y, we represent xy as
xy = f(x)= x(12 - x)
f(x) = 12x - x^2
Differentiating the above function:
f'(x) = 12 - 2x
Maximum value of f(x) occurs at point for which f'(x) = 0.
Equating f'(x) to 0 we get:
12 - 2x = 0
2x = 12
> x = 12/2 = 6
Substituting this value of x in equation (2):
y = 12 - 6 = 6
Therefore, value of xy is maximum when:
x = 6 and y = 6
The maximum value of xy = 6*6 = 36
Answer:
CED = 117
Step-by-step explanation:
21x +21 = 7x +49
21x - 7x = 49 - 21
14x = 28
x = 28/14
x = 2
7x + 49
=7(2) + 49
=14 + 49
=63
180 -63 = 117
CED= 117
Answer: u=7
Step-by-step explanation:
-6= -2u+4(u-5)
-6= -2u+4u-20
-6= 2u-20
14= 2u
7=u
