I need help please???!!!!!!!

ASAP work pls answer

maxonik [38]

C because i did it and got it right

4 0

3 years ago

-3x^2+6x+1=4 find the discriminant of each quadratic equation then state the number and type solutions

ipn [44]

Answer:

S={( 1 )}

Step-by-step explanation:

-3x²+6x+1=4

-3x²+6x+1-4=0

-3x²+6x-3=0

∆=b²-4.a.c

∆=(6)²-4.(-3).(-3)

∆=36-36

∆=0

x'=x"=-b/2a=-(+6)/2.(-3)=-6/-6=1

3 0

3 years ago

Read 2 more answers

Write the polar coordinates (3, pi) in rectangular form. a. (0, 3) c. (-3, 0) b. (3, 0) d. (0, -3)

Misha Larkins [42]

In rectangular form, we have the coordinates $(3\cos\pi,3\sin\pi)=(3\cdot -1,3\cdot 0)=\boxed{(-3,0)}.$

3 0

2 years ago

For an angle 0 with the point (-20,-21) on its terminating side, what is the value of cosine ?

Karo-lina-s [1.5K]

check the picture below.

$\bf (\stackrel{a}{-20},\stackrel{b}{-21})\impliedby \textit{let's find the \underline{hypotenuse}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=\sqrt{a^2+b^2} \qquad \begin{cases} c=hypotenuse\\ a=\stackrel{adjacent}{-20}\\ b=\stackrel{opposite}{-21}\\ \end{cases} \\\\\\ c=\sqrt{(-20)^2+(-21)^2}\implies c=\sqrt{841}\implies c=29 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill cos(\theta )=\cfrac{\stackrel{adjacent}{-20}}{\stackrel{hypotenuse}{29}}~\hfill$

5 0

3 years ago

For which values of s would the product of s/5 ×10 be greater than 10?

Neporo4naja [7]

Answer:

so I hope we're on understanding that I don't actually know the answer you know you have to earn points on this app so to like for it to keep answering your questions I've only done this once I'm so sorry yeahso we're going to be honest I don't really know the answer but good luck and I'm sorry for wasting your time so

Step-by-step explanation:

so I hope we're on understanding that I don't actually know the answer you know you have to earn points on this app so to like for it to keep answering your questions I've only done this once I'm so sorry yeahso we're going to be honest I don't really know the answer but good luck and I'm sorry for wasting your time so

6 0

3 years ago