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MissTica
3 years ago
8

Calculate the ph of a solution that is 0.295 m in sodium formate (nahco2) and 0.205 m in formic acid (hco2h). the ka of formic a

cid is 1.77 ⋅ 10-4.
Chemistry
1 answer:
Evgesh-ka [11]3 years ago
7 0
Hello!

The chemical reaction for the dissociation of Formic Acid is the following:

HCOOH + H₂O ⇄ HCOO⁻ + H₃O⁺

From this reaction we can use the Henderson-Hasselbach equation to find the pH, but first we need to find the value for the pKa:

pKa=-log(Ka)=3,75

pH=pKa + log([HCOO⁻]/[HCOOH])

pH=3,75 + log (0,295/0,205)

pH= 3,90

Have a nice day!

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