Answer:
a. 2954g of FeS
b. 1143g of FeS
Explanation:
Based on the reaction:
8 Fe + S₈ → 8 FeS
<em>8 moles of Fe reacts with 1 mole of S₈ to produce 8 moles of FeS</em>
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a. 4.2mol sulfur produce:
4.2mol S₈ × ( 8 mol FeS / 1 mol S₈) = <em>33.6mol FeS</em>. As molar mass of FeS is 87.92g/mol, mass is:
33.6mol FeS × ( 87.92g / 1 mol FeS) = <em>2954g of FeS</em>
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b. 13mol Fe produce:
13mol Fe × ( 8 mol FeS / 8 mol Fe) = <em>13mol FeS</em>. In mass:
13 mol FeS × ( 87.92g / 1 mol FeS) = <em>1143g of FeS</em>
Answer:
C: No correct response
Explanation:
Bond length is simply defined as the distance between two atoms that are participating in a bond.
Now, looking at the options, none of the options correctly defines it this way. The closest is option E which is "distance between two electrons" but it uses the word electrons instead of atoms. Thus none of the statements are correct
The answer is 0.405 M/s
- (1/3) d[O2]/dt = 1/2 d[N2]/dt
- d[O2]/dt = 3/2 d[N2]/dt
- d[O2]/dt = 3/2 × 0.27
- d[O2]/dt = 0.405 mol L^(-1) s^(-1)
Answer:
mass= 14kg
Explanation:
density= mass/volume
so that means mass= volume x density
m= 2kg/m³ x 7m³
m= 14 kg
Hope this helps
Answer:
2.9 grams.
Explanation:
- From the balanced reaction:
<em>Mg + 1/2O₂ → MgO,</em>
1.0 mole of Mg reacts with 0.5 mole of oxygen to produce 1.0 mole of MgO.
- We need to calculate the no. of moles of (1.8 g) of Mg and (6.0 g) of oxygen:
no. of moles of Mg = mass/molar mass = (1.8 g)/(24.3 g/mol) = 0.074 mol.
no. of moles of O₂ = mass/molar mass = (6.0 g)/(16.0 g/mol) = 0.375 mol.
<em>So. 0.074 mol of Mg reacts completely with (0.074/2 = 0.037 mol) of O₂ which be in excess.</em>
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<em><u>Using cross multiplication:</u></em>
1.0 mole of Mg produce → 1.0 mol of MgO.
∴ 0.074 mol of Mg produce → 0.074 mol of MgO.
<em>∴ The amount of MgO produced = no. of moles x molar mass </em>= (0.074 mol)(40.3 g/mol) = <em>2.98 g.</em>
