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MissTica
4 years ago
8

Calculate the ph of a solution that is 0.295 m in sodium formate (nahco2) and 0.205 m in formic acid (hco2h). the ka of formic a

cid is 1.77 ⋅ 10-4.
Chemistry
1 answer:
Evgesh-ka [11]4 years ago
7 0
Hello!

The chemical reaction for the dissociation of Formic Acid is the following:

HCOOH + H₂O ⇄ HCOO⁻ + H₃O⁺

From this reaction we can use the Henderson-Hasselbach equation to find the pH, but first we need to find the value for the pKa:

pKa=-log(Ka)=3,75

pH=pKa + log([HCOO⁻]/[HCOOH])

pH=3,75 + log (0,295/0,205)

pH= 3,90

Have a nice day!

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We have the value of  

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How many anions are in 0.500 g of MgBr2
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<u>Given:</u>

Mass of MgBr2 = 0.500 g

<u>To determine:</u>

Number of anions in 0.500 g MgBr2

<u>Explanation:</u>

Molar mass of MgBr2 = 24 + 2 (80) = 184 g/mol

Moles of MgBr2 = 0.500 g/184 g.mol-1 = 0.00271 moles

Based on stoichiometry-

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Ans: There are 3.264*10²¹ anions in 0.5 g of MgBr2


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