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Mrrafil [7]
3 years ago
5

How many grams are in .11 moles of Cu

Chemistry
1 answer:
kodGreya [7K]3 years ago
5 0

Answer:

m= 6.9905 = 7 g

Explanation:

The formula is m= M.n

m= mass (g), M= Molar mass (g/mole), n= moles (moles)

Molar mass of Cu is 63.55

=) m= 63.55*0.11

   m= 6.9905 = 7 g

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As methane burns, it reacts with oxygen and forms carbon dioxide and water. The balanced chemical equation below models this che
Elan Coil [88]

Explanation:

hope this helps please like and mark as brainliest

3 0
2 years ago
explain why elements lying on the extreme right of the periodic table as from non metals but those lying on the extreme left a s
kvasek [131]
Element at Extreme Left In Periodic Table:
                                                                   The elements of Group I-A (1) are present at extreme left of the periodic table. They are called as Alkali Metals. Alkali Metals are strong metals. These elements can easily loose their valence electron. The valence shell electronic configuration of these elements is,

                                                     ns¹

where n is principle quantum number, which shows main energy level or shell. These metals can gain Noble gas configuration (stable configuration) either by loosing one electron or by gaining seven or more electrons. As it is quite reasonable to loose one electron instead of gaining seven or more electrons so these element easily loose one electron to gain noble as configuration. The Metallic character decreases along the period from left to right. So Group II-A (2) are second most metallic elements and so on. These metals at extreme left mainly exist in solid form.

Element at Extreme Right In Periodic Table:
                                                                     Elements present at extreme right of the periodic table lacks the properties of metallic character and act as non-Metals. They have almost complete outermost shell or have the deficiency of one or two electrons. They are not as hard as metallic elements and they exist with complete octet like in Noble gases, or deficient with one electron (Halogens) or two electrons (oxygen group). These elements tend to gain or accept electron if their valence shell is deficient with required number of elements. Like the valence electronic configuration of Halogens is,

                                                   ns², np⁵

So, Halogens readily accept one electron and attain noble gas configuration. Elements at extreme left exist mainly in gas phase.
5 0
3 years ago
What is one similarity between metals and metalloids?
Arturiano [62]

The correct answer that explains similarities between metal and Metalloids as regards the question is They both conduct electricity

  • Metalloids can be regarded as elements that are  similar to metals, this is because they posses valence orbitals which is described as highly delocalized over macroscopic volumes.

  • As a result of this they can serve as electrical conductors.

  • metalloids posses small energy gap which is located between the valence band as well as the conduction band, as a result of this they are considered as  intrinsic semiconductors when compare to pure conductors like metal.

  • Example of metal is Calcium, sodium and that of Metalloids are silicon and  germanium

Therefore, metal and Metalloids are similar because of their conductivity of electricity

Learn more at: brainly.com/question/21036799?referrer=searchResults

4 0
2 years ago
Estimate the number of moles of water in all the Earth's oceans. Assume water covers 75% of the Earth to an average depth of 3 k
o-na [289]

Answer:

there are approximately n ≈ 10²² moles

Explanation:

Since the radius of the earth is approximately R=6378 km= 6.378*10⁶ m , then the surface S of the earth would be

S= 4*π*R²

since the water covers 75% of the Earth's surface , the surface covered by water Sw is

Sw=0.75*S

the volume for a surface Sw and a depth D= 3 km = 3000 m ( approximating the volume through a rectangular shape) is

V=Sw*D

the mass of water under a volume V , assuming a density ρ= 1000 kg/m³ is

m=ρ*V

the number of moles n of water ( molecular weight M= 18 g/mole = 1.8*10⁻² kg/mole ) for a mass m is

n = m/M

then

n = m/M = ρ*V/M = ρ*Sw*D/M = 0.75*ρ*S*D/M = 3/4*ρ*4*π*R² *D/M = 3*π*ρ*R² *D/M

n=3*π*ρ*R² *D/M

replacing values

n=3*π*ρ*R² *D/M = 3*π*1000 kg/m³*(6.378*10⁶ m)² *3000 m /(1.8*10⁻² kg/mole) = 3*π*6.378*3/1.8 * 10²⁰ = 100.18 * 10²⁰ ≈ 10²² moles

n ≈ 10²² moles

8 0
3 years ago
Given the following information: benzoic acid = C6H5COOH hydrocyanic acid = HCN C6H5COOH is a stronger acid than HCN (1) Write t
Maurinko [17]

Answer:

The net ionic equation is

C6H5COOH+ CN-= C6H5COO- + HCN

Explanation:

From the ionic equation

C6H5COOH + Na+ + CN- = C6H5COO- + Na+ + HCN

Only sodium is the spectator ion, so it cancels out, since C6H5COOH and HCN do not ionize completely they are left undissociated

5 0
3 years ago
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