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2 years ago

1. f(x) = (x 81+2 What is the domain?

Mathematics

1 answer:

kaheart [24]2 years ago

4 0

Answer

by interval notation answer would be: (-∞,∞)

Step-by-step explanation:

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Points X and Z are on a number line, and point Y partitions line XZ into two parts so that the ratio of the length of line segme

hram777 [196]

Answer:

Step-by-step explanation:

if Points X and Z are on a number line and point Y partition line XZ into two parts where XY: YZ = 1:4, this can be expressed as;

XY/YZ = 1/4

cross multiply;

YZ = 4XY

Also, if The coordinate of X is 1.3, and the coordinate of Y is 3.8, then the distance XY will be expressed as XY = 3.8 - 1.3

XY = 2.5

YZ = 4(2.5)

YZ = 10

Since Y is at 3.8 and YZ is 10, then coordinate Z will be YZ + Y

coordinate of Z = 10+3.8

coordinate of Z = 13.8

7 0

2 years ago

An automatic machine is set to fill bags of dog food with exactly 25 pounds on average with a standard deviation of 0.5 pounds.

Rasek [7]

Answer:

Step-by-step explanation:

Given that an automatic machine is set to fill bags of dog food with exactly 25 pounds on average with a standard deviation of 0.5 pounds.

Sample size = n =100

x bar = 24.85 pounds

Sample std error = $\frac{\sigma}{\sqrt{n} } =0.05$

Hypotheses:

$H_0: x bar = 25\\H_a: x bar \neq 25$

(Two tailed test at 5% level)

Mean difference =0.15

Test statistic = mean diff/se = 3

Since population std dev is known z test can be used

p value =0.0000

Since p <0.05 we find that the bag does not contain exactly 25 pounds.

5 0

2 years ago

How do you prove the two triangles congruent?

bazaltina [42]

5 ideas
1.SSS (side, side, side) SSS stands for "side, side, side" and means that we have two triangles with all three sides equal. ...
2.SAS (side, angle, side) ...
3.ASA (angle, side, angle) ...
4.AAS (angle, angle, side) ...
5.HL (hypotenuse, leg)

3 0

2 years ago

Mary wants to join a gym.

Leya [2.2K]

Answer:

It would take five months for the total cost of the gyms to be equal.

Step-by-step explanation:

5 0

1 year ago

At what point does the curve have maximum curvature? Y = 4ex (x, y) = what happens to the curvature as x → ∞? Κ(x) approaches as

MAXImum [283]

<u>Answer-</u>

At $x= \frac{1}{2304e^4-16e^2}$ the curve has maximum curvature.

<u>Solution-</u>

The formula for curvature =

$K(x)=\frac{{y}''}{(1+({y}')^2)^{\frac{3}{2}}}$

Here,

$y=4e^{x}$

Then,

${y}' = 4e^{x} \ and \ {y}''=4e^{x}$

Putting the values,

$K(x)=\frac{{4e^{x}}}{(1+(4e^{x})^2)^{\frac{3}{2}}} = \frac{{4e^{x}}}{(1+16e^{2x})^{\frac{3}{2}}}$

Now, in order to get the max curvature value, we have to calculate the first derivative of this function and then to get where its value is max, we have to equate it to 0.

${k}'(x) = \frac{(1+16e^{2x})^{\frac{3}{2} } (4e^{x})-(4e^{x})(\frac{3}{2}(1+e^{2x})^{\frac{1}{2}})(32e^{2x})}{(1+16e^{2x} )^{2}}$

Now, equating this to 0

$(1+16e^{2x})^{\frac{3}{2} } (4e^{x})-(4e^{x})(\frac{3}{2}(1+e^{2x})^{\frac{1}{2}})(32e^{2x}) =0$

$\Rightarrow (1+16e^{2x})^{\frac{3}{2}}-(\frac{3}{2}(1+e^{2x})^{\frac{1}{2}})(32e^{2x})$

$\Rightarrow (1+16e^{2x})^{\frac{3}{2}}=(\frac{3}{2}(1+e^{2x})^{\frac{1}{2}})(32e^{2x})$

$\Rightarrow (1+16e^{2x})^{\frac{1}{2}}=48e^{2x}$

$\Rightarrow (1+16e^{2x})}=48^2e^{2x}=2304e^{2x}$

$\Rightarrow 2304e^{2x}-16e^{2x}-1=0$

Solving this eq,

we get $x= \frac{1}{2304e^4-16e^2}$

∴ At $x= \frac{1}{2304e^4-16e^2}$ the curvature is maximum.

6 0

2 years ago