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irina1246 [14]
3 years ago
12

The mass of Planet X is one-tenth that of the earth, and its diameter is one-half that of the earth. the acceleration due to gra

vity at the surface of Planet X is most nearly...
Physics
1 answer:
guapka [62]3 years ago
5 0

Fg=(G*M1*M2)/(r^2)

(1/10)/(1/2^2)=4/10=2/5

Planet X is approx 2/5 of earth’s gravity

9.8m/s^2 * 2/5 = 3.92m/s^2

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a container of water is knocked off a 10.0 meter high ledge with a horizontal velocity of 1.00 meters/second. calculate the time
Evgen [1.6K]

Answer:

1.43 s

Explanation:

The time it takes for the container to reach the ground is determined only by the vertical motion of the container, which is a free-fall motion, so a uniformly accelerated motion with a constant acceleration of g=9.8 m/s^2 towards the ground.

The vertical distance covered by an object in free fall is given by

S=ut + \frac{1}{2}at^2

where

u = 0 is the initial vertical speed

t is the time

a= g = 9.8 m/s^2 is the acceleration

since u=0, it can be rewritten as

S=\frac{1}{2}gt^2

And substituting S=10.0 m, we can solve for t, to find the duration of the fall:

t=\sqrt{\frac{2S}{g}}=\sqrt{\frac{2(10.0 m)}{9.8 m/s^2}}=1.43 s

3 0
3 years ago
Snow and sleet when they fall to the ground is solar energy or gravitational force?
Nikolay [14]

Gravitational energy

3 0
3 years ago
A 65.0 kg football player is running at 10.0 m/s downfield when he catches a 0.420 kg football thrown in the same direction but
lukranit [14]

Explanation:

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8 0
3 years ago
Which of the following is not a major function of the roots?
sashaice [31]

it is c. it is photosynthesis because is under the ground and away from the sun

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Two carts, one of mass 2m and one of mass m, approach each other with the same speed, v. When the carts collide, they hook toget
Nikitich [7]

Answer:

<em>Second option</em>

Explanation:

<u>Linear Momentum</u>

The linear momentum of an object of mass m and speed v is

P=mv

If two or more objects are interacting in the same axis, the total momentum is

P_t=m_1v_1+m_2v_2+...

Where the speeds must be signed according to a fixed reference

The images show a cart of mass 2m moves to the left with speed v since our reference is positive to the right

P_1=-2mv

The second cart of mass m goes to the right at a speed v

P_2=mv

The total momentum before the impact is

P_t=-2mv+mv=-mv

The total momentum after the collision is negative, both carts will join and go to the left side

The first option shows both carts with the same momentum before the collision and therefore, zero momentum after. It's not correct as we have already proven

The third option shows the 2m cart has a positive greater momentum than the other one. We have proven the 2m car has negative momentum. This option is not correct either

The fourth option shows the two carts keep separated after the collision, which contradicts the condition of the question regarding "they hook together".

The second option is the correct one because the mass m_2 has a negative momentum and then the sum of both masses keeps being negative

3 0
3 years ago
Read 2 more answers
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