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Goshia [24]
3 years ago
10

In a crash test, a 1000 kg automobile moving at 10 m/s crashes into a brick wall. How much energy goes into demolishing and warm

ing the wall and the auto?
Physics
1 answer:
marishachu [46]3 years ago
8 0

Answer:

Explanation:

Given

mass of automobile m=1000\ kg

velocity of automobile v=10\ m/s

If the automobile crashes into the brick wall then it's kinetic energy is converted into thermal and demolishing energy to wall.

Car completely stops as it crashes into the wall so Energy converted into demolition and thermal energy

E=\frac{1}{2}mv^2

E=\frac{1}{2}\times 1000\times (10)^2

E=50\ kJ  

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what is the focalength of the combination of two thin renses of power -5D and -2D placeci in contact with each other?​
Ghella [55]

Answer:

f = - 0.143 m = - 14.3 cm

Explanation:

First, we will calculate the power of the combination of lenses:

P = P₁ + P₂

where,

P = Power of Combination = ?

P₁ = Power of first lens = - 5D

P₂ = Power of second lens = - 2D

Therefore,

P = - 5D - 2D

P = - 7D

Now, the focal length can be given as:

f = \frac{1}{P} \\\\f = \frac{1}{-\ 7\ D} \\\\

<u>f = - 0.143 m = - 14.3 cm</u>

Negative focal length indicates that combination will act as diverging lens.

6 0
3 years ago
A 0.40 kg object is attached to a spring with force constant 157 N/m so that the object is allowed to move on a horizontal frict
nirvana33 [79]

Answer:

Part a)

F = 26.7 N

Part b)

a = 66.7 m/s^2

Explanation:

Part a)

Force on the object due to spring force is given as

F = kx

here we know that

k = 157 N/m

x = 0.17 m

so we have

F = 157\times 0.17

F = 26.7 N

Part b)

Acceleration of the object is given as

a = \frac{F}{m}

a = \frac{26.7}{0.40}

a = 66.7 m/s^2

8 0
3 years ago
When the moon slowly moves away from the earth.How is it affecting the gravitational force between the earth and the moon?
sukhopar [10]
Well, think about how the tides will be affected when the moon moves farther away. If the moon first started off very close the earth, we would have more tsunamis. (Scientists have found that the moon has possibly been closer to earth long ago.) While it moves away, soon there will no longer be many tides.
3 0
3 years ago
The water from a fire hose follows a path described by y equals 3.0 plus 0.8 x minus 0.40 x squared ​(units are in​ meters). If
ivanzaharov [21]

Explanation:

It is given that, the water from a fire hose follows a path described by equation :

y=3+0.8x-0.4x^2........(1)

The x component of constant velocity, v_x=5\ m/s

We need to find the resultant velocity at the point (2,3).

Let \dfrac{dx}{dt}=v_x and \dfrac{dy}{dt}=v_y

Differentiating equation (1) wrt t as,

\dfrac{dy}{dt}=0.8\times \dfrac{dx}{dt}-0.8x\times \dfrac{dx}{dt}

v_y=0.8\times v_x-0.8x\times v_x

v_y=0.8v_x(1-x)

When x = 2 and v_x=5\ m/s

So,

v_y=0.8\times 5\times (1-2)

v_y=-4\ m/s

Resultant velocity, v=\sqrt{v_x^2+v_y^2}

v=\sqrt{5^2+(-4)^2}

v = 6.4 m/s

So, the resultant velocity at point (2,3) is 6.4 m/s. Hence, this is the required solution.

8 0
3 years ago
If you throw an object straight up into the air with an initial velocity of 42m/s. What is it’s velocity at the peak of its fl
solniwko [45]
0 m/s. It’s trivial
7 0
3 years ago
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