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____ [38]
3 years ago
12

Write a balanced equation for the combustion of isooctane,C8 H16 a component of gasoline.

Chemistry
1 answer:
algol133 years ago
5 0

<u>Answer:</u> The balanced chemical equation for the combustion of isooctane is written below.

<u>Explanation:</u>

Combustion reactions are defined as the reactions in which a hydrocarbon reacts with oxygen gas to produce carbon dioxide and water. Heat is released during these reactions.

A balanced chemical equation is defined as the equation in which total number of individual atoms on the reactant side is equal to the total number of individual atoms on product side.

The balanced chemical equation for the combustion of isooctane follows:

C_8H_{16}+12O_2\rightarrow 8CO_2+8H_2O

By Stoichiometry of the reaction:

1 mole of isooctane reacts with 12 moles of oxygen gas to produce 8 moles of carbon dioxide and 8 moles of water molecule.

Hence, the balanced chemical equation for the combustion of isooctane is written above.

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11) What is the volume of 4.92 grams of hydrogen gas at STP? (Show the work using dimensional analysis)
lorasvet [3.4K]

Answer:

The volume of 4.92 grams of hydrogen gas at STP is 9.105 litter.

Explanation:

We know that, the molecular weight of hydrogen gas (H_{2} ) = 1\times 2 = 2.

Moles of hydrogen gas = \frac{weight}{molecular weight}  = \frac{4.92}{2} = 2.46 moles.

At STP, 1 mole of hydrogen gas = occupies 22.4 litter

    So, 2.46 mole of hydrogen gas = occupies \frac{22.4}{2.46} = 9.105 litter.

Hence, the volume of 2.46 grams of hydrogen gas at STP is 9.105 litter.

4 0
3 years ago
A solution of hydrochloric acid is mixed with an equal volume solution of barium hydroxide. When pH paper is inserted into the r
Dennis_Churaev [7]
The balanced equation for the reaction between Ba(OH)₂ and HCl is ;
Ba(OH)₂ + 2HCl ----> BaCl₂ + 2H₂O
When equal volumes of both acid and base are added, the pH is 7 which means its neutral. 
This means that the H⁺ ions and OH⁻ are equal and they have neutralised each other. All the ions have reacted to form water molecules.
Dissociation of base and acid are as follows;
Ba(OH)₂ ---> Ba²⁺ + 2OH⁻
1 mol of Ba(OH)₂ dissociates to 2 mol H⁺
HCl ---> H⁺ + Cl⁻
n moles of HCl give out n mol of H⁺ ions
H⁺ = OH⁻ which is why solution is neutral
then OH⁻ moles present are n  mol 
then Ba(OH)₂ moles present should be n/2 mol
molarity of HCl = 0.5 mol/L
since volumes are equal number of moles are directly proportional to molarity 
molarity of Ba(OH)₂ = 0.5/2 = 0.25 M
4 0
3 years ago
When two monosaccharides condense to form a disaccharide, what is the other product of the reaction? enter the molecular formula
koban [17]

When two monosaccharides combine to make a disaccharide, water is the byproduct.

<h3>What are monosaccharides ?</h3>

The most fundamental building blocks from which all carbohydrates are constructed are monosaccharides, commonly known as simple sugars. They are the most basic types of sugar. They are typically crystalline solids, colorless, and soluble in water.

These three monosaccharides—glucose, fructose, and galactose—are crucial for nutrition. Six carbon atoms, twelve hydrogen atoms, and six oxygen atoms make up each single sugar molecule.

To learn more about monosaccharides from the given link:

brainly.com/question/13416862

#SPJ4

4 0
1 year ago
Given: 36.7 grams of CaF2 is added to 300 mL water. Find molarity?
BigorU [14]
<h3>Answer:</h3>

2 M

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Unit 0</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis

<u>Aqueous Solutions</u>

  • Molarity = moles of solute / liters of solution
<h3>Explanation:</h3>

<u>Step 1: Define</u>

36.7 g CaF₂

300 mL H₂O

<u>Step 2: Identify Conversions</u>

Molar Mass of Ca - 40.08 g/mol

Molar Mass of F - 19.00 g/mol

Molar Mass of CaF₂ - 40.08 + 2(19.00) = 78.08 g/mol

1000 mL = 1 L

<u>Step 3: Convert</u>

<em>Solute</em>

  1. Set up:                               \displaystyle 36.7 \ g \ CaF_2(\frac{1 \ mol \ CaF_2}{78.08 \ g \ CaF_2})
  2. Multiply:                             \displaystyle 0.470031 \ mol \ CaF_2

<em>Solution</em>

  1. Set up:                              \displaystyle 300 \ mL \ H_2O(\frac{1 \ L \ H_2O}{1000 \ mL \ H_2O})
  2. Multiply:                            \displaystyle 0.3 \ L \ H_2O

<u>Step 4: Find Molarity</u>

  1. Substitute [M]:                    \displaystyle x \ M = \frac{0.470031 \ mol \ CaF_2}{.3 \ L \ H_2O}
  2. Divide:                                \displaystyle x = 1.56677 \ M

<u>Step 5: Check</u>

<em>Follow sig fig rules and round.</em> <em>We are given 1 sig fig as our lowest.</em>

1.56677 M ≈ 2 M

8 0
3 years ago
Please help! 30 points!
lisabon 2012 [21]
The person above me is correct
8 0
3 years ago
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