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Savatey [412]
3 years ago
14

11) What is the volume of 4.92 grams of hydrogen gas at STP? (Show the work using dimensional analysis)

Chemistry
1 answer:
lorasvet [3.4K]3 years ago
4 0

Answer:

The volume of 4.92 grams of hydrogen gas at STP is 9.105 litter.

Explanation:

We know that, the molecular weight of hydrogen gas (H_{2} ) = 1\times 2 = 2.

Moles of hydrogen gas = \frac{weight}{molecular weight}  = \frac{4.92}{2} = 2.46 moles.

At STP, 1 mole of hydrogen gas = occupies 22.4 litter

    So, 2.46 mole of hydrogen gas = occupies \frac{22.4}{2.46} = 9.105 litter.

Hence, the volume of 2.46 grams of hydrogen gas at STP is 9.105 litter.

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Describe the many different forms of energy involved with stretching and releasing a rubber band. What other processes are simil
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Answer:

Conversion of kinetic energy to potential energy (chemo mechanical energy)

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Conversion of the stored potential energy in the stretched to kinetic energy

By remaining in a stretched condition, the rubber is in a state of high potential energy, when the force holding the rubber in place is removed, due to the laws of thermodynamics, the polymers in the rubber curls back to their state of "random" tangled mass releasing the stored potential energy in the process and doing work such as moving items placed in the rubber's path of motion such as an object that has weight, w then takes up the kinetic energy 1/2×m×v² which can can result in the flight of the object.

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Which of the following electron transitions in a hydrogen atom emits light of the shortest wavelength? Circle the correct answer
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Answer:

Transition from n = 4 to n = 1  corresponds to shortest wavelength.

Explanation:

         Process                   \mid \Delta n\mid =\mid \frac{1}{(n)_{final}^{2}}-(\frac{1}{n_{initial}^{2}})\mid

             A                                         0.9375

             B                                          0.75

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             D                                          0.1875

According to Rydberg equation for electronic transition in H-like atoms:

           \frac{1}{\lambda }=R_{H}\mid (\frac{1}{n_{final}^{2}}-(\frac{1}{n_{initial}^{2}})\mid

where, \lambda is wavelength of light emitted or absorbed, R_{H} is Rydberg constant.

So, higher the value of \mid \Delta n\mid, lower will the corresponding wavelength of light.

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3 years ago
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