Two steps by inspection 1 qt = 0.25 gallons, 13.6 g/mL = 13.6 kg/L
0.25 gallon x 3.785411784 L/gallon x 13.6 kg/L x 1 lb/0.45359237 kg = 28.374 lb.
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Answer : The given compound belongs to ether and alcohol.
Explanation :
The chemical formula of the given compound is, 
First we have to calculate the degree of unsaturation.
Formula used:
Degree of unsaturation = 
where,
C = number of carbon
H = number of hydrogen
N = number of nitrogen
X = number of halogen
Degree of unsaturation = 
The degree of unsaturation is, 0 that means there is no double or triple bond in the compound only single bond is present between the atoms.
Thus, the given compound belongs to ether and alcohol.
Answer:
the same
Explanation:
due to the law of conservation of mass, the mass will not change
Explanation:
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Answer:
alkenes and alkynes are considered as unsaturated hydrocarbons because they are capable of reacting with hydrogen in the presence of a catalyst to form a saturated hydrocarbon (alkanes)
Explanation:
A saturated compound contains a chain of carbon atoms joined by single bonds, with hydrogen atoms attached to each carbon atom.
Propane for example, CH₃-CH₂-CH₃.
It is saturated because all the carbon atoms holds maximum number of hydrogen atoms.
Alkenes such as Propene (CH₂=CH-CH₃) and alkynes like Propyne,
(CH₃-C≡C-H) are unsaturated because the central carbon atoms contain less number of hydrogen atoms than they possibly could.