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Shalnov [3]
1 year ago
5

When two monosaccharides condense to form a disaccharide, what is the other product of the reaction? enter the molecular formula

.
Chemistry
1 answer:
koban [17]1 year ago
4 0

When two monosaccharides combine to make a disaccharide, water is the byproduct.

<h3>What are monosaccharides ?</h3>

The most fundamental building blocks from which all carbohydrates are constructed are monosaccharides, commonly known as simple sugars. They are the most basic types of sugar. They are typically crystalline solids, colorless, and soluble in water.

These three monosaccharides—glucose, fructose, and galactose—are crucial for nutrition. Six carbon atoms, twelve hydrogen atoms, and six oxygen atoms make up each single sugar molecule.

To learn more about monosaccharides from the given link:

brainly.com/question/13416862

#SPJ4

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What 2 things do the planets need to have in order to stay in orbit and rotate?
Degger [83]
Two things plants need to have in order to stay in orbit and rotate is speed and less velocity.
5 0
3 years ago
Use the formula: PV=nRT<br><br> If P=12, V=22.4, R=.0821 and T=100, then what would n=?
Lina20 [59]
PV=nRT \\ (12)(22.4)=n(.0821)(100) \\ 268.8=8.21n \\ 268.8/8.21=8.21n/8.21 \\ n=32.74
n ≈ 32.74
Hope this helps!
7 0
3 years ago
If the volume of wet gas collected over water is 85.0 mL at 20°C and 760 mm Hg , what is the volume of dry gas at STP conditions
dimulka [17.4K]

Answer: 77.4 mL

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is:

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of dry gas = (760 - 17.5) mmHg= 742.5 mm Hg

P_2 = final pressure of dry gas at STP =  760 mm Hg

V_1 = initial volume of dry gas = 85.0 mL

V_2 = final volume of dry gas at STP = ?

T_1 = initial temperature of dry gas = 20^oC=273+20=293K

T_2 = final temperature of dry gas at STP = 0^oC=273+0=273K

Now put all the given values in the above equation, we get the final volume of wet gas at STP

\frac{742.5mmHg\times 85.0ml}{293K}=\frac{760mmHg\times V_2}{273K}

V_2=77.4mL

Volume of dry gas at STP is 77.4 mL.

5 0
4 years ago
25. What is the molarity of an H2SO4 solution if
gizmo_the_mogwai [7]

Answer:

1

Explanation:

hope it helps:)

///////////

7 0
3 years ago
A sample of Mo(NO3)6 has 2.22 x 10^22 nitrogen atom, how many oxygen atoms does the sample have?
goldfiish [28.3K]

There are 3.98 × 10^23 atoms of oxygen in the sample.

Given that;

1 mole of Mo(NO3)6 contains 6.02 × 10^23 atoms of Nitrogen

x moles of Mo(NO3)6 contains 2.22 x 10^22 atoms of nitrogen

x = 1 mole × 2.22 x 10^22 atoms/6.02 × 10^23 atoms

x = 0.0368 moles

The number of oxygen atoms in the sample is given by; 0.0368 × 6.02 × 10^23 × 18

Therefore, there are 3.98 × 10^23 atoms of oxygen in the sample.

Learn more: brainly.com/question/9743981

4 0
2 years ago
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