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Mariulka [41]
3 years ago
5

Why are protists that are heterotrophs considered "animal-like"? A they make their own food. B They don't need energy C They fee

d on other organisms.
Chemistry
1 answer:
goblinko [34]3 years ago
8 0

Answer:

A, Animal-like protists are called protozoa. ... Like animals, they can move, and they are heterotrophs. That means they eat things outside of themselves instead of producing their own food

Explanation:

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Maggie is sitting at a table wit Fred and Florence.Maggie has 10 markers but Fred and Florence each have only 7 markers.how can
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Is each of these statements true? If not, explain why.(g) The rate of a reaction increases as the reaction proceeds.
Elina [12.6K]

The rate of a reaction rises as it progresses. The answer is false

<h3>What causes a reaction's rate to increase?</h3>

Generally speaking, raising the temperature of the reaction system, raising the concentration of a reactant in solution, and raising the surface area of a solid reactant will all raise the rate of a reaction. A catalyst can be added to the reaction mixture to speed up a process as well.

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7 0
1 year ago
Balance the following redox reaction in acidic solution. Zn(s)+MnO−4(aq)→ Zn+2(aq)+Mn+2(aq)
devlian [24]

Answer:

2MnO₄⁻ + 5Zn + 16H⁺ → 2Mn²⁺ + 8H₂O + 5Zn²⁺

Explanation:

To balance a redox reaction in an acidic medium, we simply follow some rules:

  1. Split the reaction into an oxidation and reduction half.
  2. By inspecting, balance the half equations with respect to the charges and atoms.
  3. In acidic medium, one atom of H₂O is used to balance up each oxygen atom and one H⁺ balances up each hydrogen atom on the deficient side of the equation.
  4. Use electrons to balance the charges. Add the appropriate numbers of electrons the side with more charge and obtain a uniform charge on both sides.
  5. Multiply both equations with appropriate factors to balance the electrons in the two half equations.
  6. Add up the balanced half equations and cancel out any specie that occur on both sides.
  7. Check to see if the charge and atoms are balanced.

Solution

                            Zn + MnO₄⁻ → Zn²⁺ + Mn²⁺

The half equations:

                      Zn → Zn²⁺                          Oxidation half

                      MnO₄⁻ → Mn²⁺                  Reduction half

Balancing of atoms(in acidic medium)

                     Zn → Zn²⁺

                    MnO₄⁻ + 8H⁺ → Mn²⁺ + 4H₂O

Balancing of charge

                   Zn → Zn²⁺ + 2e⁻

                    MnO₄⁻ + 8H⁺ + 5e⁻→ Mn²⁺ + 4H₂O

Balancing of electrons

         Multiply the oxidation half by 5 and reduction half by 2:

                          5Zn → 5Zn²⁺ + 10e⁻

                        2MnO₄⁻ + 16H⁺ + 10e⁻→ 2Mn²⁺ + 8H₂O

Adding up the two equations gives:

              5Zn + 2MnO₄⁻ + 16H⁺ + 10e⁻ → 5Zn²⁺ + 10e⁻ + 2Mn²⁺ + 8H₂O

The net equation gives:

         5Zn + 2MnO₄⁻ + 16H⁺ → 5Zn²⁺ + 2Mn²⁺ + 8H₂O

8 0
3 years ago
Which of these contains information about the elements
Monica [59]
Post the question so we can help
7 0
3 years ago
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