Answer:
Step 1: Determine the goal of the algorithm. ...
Step 2: Access historic and current data. ...
Step 3: Choose the right model(s) ...
Step 4: Fine tuning. ...
Step 5: Visualise your results. ...
Step 6: Running your algorithm continuously.
Answer:
II and III only
Explanation:
In Code segment II, the output of the array will be started form arr[0] and ends at the arr[length]. Because loop starts from 0 and ends at length of array. This will print the full array data.
In code segment III, the output will be all values of array as loop starts form first index and ends at last index.
On the other hand I code segment prints all array values except last value of the array. As the loop shows that, it will terminate at second last value of the array.
Answer:
I did this in C# & Java
Explanation:
C#:
public static void Main(string[] args)
{
int input = Convert.ToInt32(Console.ReadLine());
Multiply(input);
}
public static int Multiply(int input)
{
int ans = 0;
for(int i =1; i<=10; i++)
{
ans = i*input;
Console.WriteLine(i + "*" + input + "=" + ans);
}
return ans;
}
Java:
public static void main(String[] args)
{
Scanner myObj = new Scanner(System.in);
int input = Integer.parseInt(myObj.nextLine());
Multiply(input);
}
public static int Multiply(int input)
{
int ans = 0;
for(int i =1; i<=10; i++)
{
ans = i*input;
System.out.println(i + "*" + input + "=" + ans);
}
return ans;
}
Answer:
#include <iostream>
using namespace std;
int main() {
int a[4][5];//declaring a matrix of 4 rows and 5 columns.
for(int i=0;i<4;i++)
{
for(int j=0;j<5;j++)
{
if(i==3)//initializing last row as 0.
{
a[i][j]=0;
}
else//initializing last row as 1.
{
a[i][j]=1;
}
}
}
for(int i=0;i<4;i++)
{
for(int j=0;j<5;j++)
cout<<a[i][j]<<" ";//printing the matrix.
cout<<endl;
}
return 0;
}
Output:-
1 1 1 1 1
1 1 1 1 1
1 1 1 1 1
0 0 0 0 0
Explanation:
I have created a matrix of size 4 rows and 5 columns.I have used for loops to fill the array.To fill the last row with 0 i have used if statement.else we are filling it with 1.
There are a few consequences for failing to identify system requirements.
1. Strain on time and effort which can cost money for either a company or yourself (depending if you are an employer, employee, etc).
2. Additional costs for hardware. If you decide to upgrade your hardware on a later time. It will cost additional money for repairs and replacements to adjust.
3. It can cause dissatisfaction to a user if you are working as a technician (for example) which can leave a negative mark on your reputation/resume)
