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Alex787 [66]
3 years ago
15

Which is a chemical property of iron?

Chemistry
2 answers:
Marta_Voda [28]3 years ago
7 0
I believe it would be the first option. It forms iron oxide (rust) when exposed to moisture and air.
AleksAgata [21]3 years ago
7 0

The answer is A, It forms iron oxide (rust) when exposed to moisture and air. Every other option describes a physical property of iron.


I hope this helped xoxox

- Lauren

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What change in mass number occurs when a radioactive atom emits an alpha particle?
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The alpha particle is the helium nucleus.
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The mass of radioactive atom decreases by 4u. Look at the reaction below:

²²³₈₈Ra ---> ⁴₂He + ²¹⁹₈₆Rn
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3 years ago
HCl gas is introduced at one end of the tube, and simultaneously NH3 gas is introduced at the other end. When the two gases diff
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When the two gases are mixed, the ammonium chloride precipitates in the tube walls.

Explanation:

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HCl (g)  +  NH₃(g)  →  NH₄Cl (s) ↓

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Which statement defines activation energy?
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7 0
3 years ago
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A gas has a volume of 25.0 mL when under a pressure of 525 mmHg. What is the new pressure when the volume has been increased to
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152.26 mmHg

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5 0
3 years ago
For the reaction shown, calculate how many grams of oxygen form when each quantity of reactant completely reacts.
Nikolay [14]

Explanation:

Molar mass of KClO_{3} = 39.1 + 35.5 + 3(16.0) = 122.6 g

Molar mass of KCl = 39.1 + 35.5 = 74.6 g

Molar mass of O_{2} = 32.0 g

According to the equation, 2 moles of KClO_{3} reacts to give 3 moles of oxygen.

Therefore, 2 (122.6) = 245.2 g of KClO_{3} will give 3 (32.0) = 96.0 g of oxygen. Thus, 245.2 g of KClO_{3} gives 96.0 g of oxygen.

(a) Calculate the amount of oxygen given by 2.72 g of KClO_{3} as follows.

       \frac {96g}{245.2g} \times 2.72 g = 1.06 g of O_{2}


(b) Calculate the amount of oxygen given by 0.361 g of KClO_{3} as follows.

    \frac {96g}{245.2g} \times 0.361 g = 0.141 g of O_{2}


c) Calculate the amount of oxygen given by 83.6 kg KClO_{3} as follows.  

    \frac {96g}{245.2g} \times 83.6 g = 32.731 kg of O_{2}

Convert kg into grams as follows.

    \frac{32.731 kg}{1 kg} \times 1000 g = 32731 g of O_{2}


(d) Calculate the amount of oxygen given by 22.5 mg of KClO_{3} as follows.  

    \frac {96g}{245.2g} \times 22.5 mg = 8.79 mg

Convert mg into grams as follows.

  \frac{8.79 mg}{1 mg}\times 10^{-3} g = 8.79 \times 10^{-3} g of O_{2}

8 0
3 years ago
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