Answer:
= 100u. Hence 10 g = 0.1 mole. Hope it's helpful to u
0.3147 concentration (in moles/l) of a saline (NaCl) solution will provide an isotonic eyedrop solution.
Isotonic eye drops
Because it might result in eye discomfort or tissue damage if it is not maintained, isotonicity is regarded as a crucial component of ophthalmic medicines. A few drops of blood are mixed with the test preparation before being examined and judged under a microscope at a magnification of 40. Isotonic solutions are those that have the same amount of water and other solutes in them as the cytoplasm of a cell. Since there is no net gain or loss of water, placing cells in an isotonic solution will not cause them to either shrink or swell.
We can calculate the osmotic pressure exerted by a solution using the following expression.
π = M . R . T
where,
π is the osmotic pressure
M is the molar concentration of the solution
R is the ideal gas constant
T is the absolute temperature
The absolute temperature is 37 + 273 = 310 K
π = M . R . T
8 = (X mol/L) . (0.082atm.L/mol.K) . 310 K = 0.3147 mol/L
To learn more about osmotic pressure refer:
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Chemical energy to thermal
Answer:
1.60.
Explanation:
- The no. of millimoles of HCl = MV = (0.15 M)(20.0 mL) = 3.0 mmol.
- The no. of millimoles of KOH = MV = (0.10 M)(20.0 mL) = 2.0 mmol.
<em>Since the no. of millimoles of HCl is larger than that of KOH. The solution is acidic.</em>
<em></em>
∴ M of remaining HCl [H⁺] remaining = (NV)HCl - (NV)KOH/V total = (3.0 mmol) - (2.0 mmol) / (40.0 mL) = 0.025 M.
∵ pH = - log[H⁺]
<em>∴ pH = - log[H⁺] </em>= - log(0.025) = <em>1.602 ≅ 1.60.</em>
Answer:
up down up down thats the pattern
Explanation:
