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bixtya [17]
3 years ago
15

What is the atomic number and the mass number of an atom with 11 protons and 12 neutrons?

Chemistry
1 answer:
sleet_krkn [62]3 years ago
8 0

Answer:

e

Explanation:

e

e

e

e

ee

e

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The element Y has 13 electrons. What is the electronic configuration of
enyata [817]

Answer:

0,2,8,3

Explanation:

k shell takes 2,L shell takes 8 and M shell takes the remaining which is 3

5 0
3 years ago
What is the concentration of a solution formed by diluting 25.0 ml of a 3.2 M NaCl solution to 135.0 ml?
Irina-Kira [14]

Answer:

B) 0.59 M NaCl.

Explanation:

  • It is known that the no. of millimoles of NaCl before dilution = the no. of millimoles of NaCl after dilution.

∵ (MV) before dilution = (MV) after dilution.

<em>∴ M after dilution = (MV) before dilution / V after dilution </em>= (3.2 M)(25.0 mL)/(135.0 mL) = <em>0.5926 M ≅ 0.59 M.</em>

4 0
3 years ago
Read 2 more answers
Given the Henry’s law constant for O2(4.34*109Pa) at 25° C, calculate the molar concentration of oxygen in air-saturated and O2s
Flauer [41]

This is an incomplete question, here is a complete question.

The Henry's law constant for oxygen dissolved in water is 4.34 × 10⁹ g/L.Pa at 25⁰C.If the partial pressure of oxygen in air is 0.2 atm, under atmospheric conditions, calculate the molar concentration of oxygen in air-saturated and oxygen saturated water.

Answer : The molar concentration of oxygen is, 2.67\times 10^2mol/L

Explanation :

As we know that,

C_{O_2}=k_H\times p_{O_2}

where,

C_{O_2} = molar solubility of O_2 = ?

p_{O_2} = partial pressure of O_2 = 0.2 atm  = 1.97×10⁻⁶ Pa

k_H = Henry's law constant  = 4.34 × 10⁹ g/L.Pa

Now put all the given values in the above formula, we get:

C_{O_2}=(4.34\times 10^9g/L.Pa)\times (1.97\times 10^{-6}Pa)

C_{O_2}=8.55\times 10^3g/L

Now we have to molar concentration of oxygen.

Molar concentration of oxygen = \frac{8.55\times 10^3g/L}{32g/mol}=2.67\times 10^2mol/L

Therefore, the molar concentration of oxygen is, 2.67\times 10^2mol/L

8 0
3 years ago
Sam investigates the reactivity of metals in air. His observations are shown below.
viva [34]

Answer:5

Explanation:

6 0
2 years ago
Read 2 more answers
An atom holds 7 electrons. use orbital notation to model the probable location of its electrons.
zheka24 [161]

Answers:

(a) 1s² 2s²2p³; (b) 1s² 2s²2p⁶ 3s²3p⁶ 4s²3d²; (c) 1s² 2s²2p⁶ 3s²3p⁵

Step-by-step explanation:

One way to solve this problem is to add electrons to the orbitals one-by-one until you have added the required amount.

Fill the subshells in the order listed in the diagram below. Remember that an s subshell can hold two electrons, while a p subshell can hold six, and a d subshell can hold  ten.

(a) <em>Seven electrons </em>

1s² 2s²2p³

There are two electrons in the 2s subshell and three in the 2p subshell. The remaining two electrons are in the inner 1s subshell.

(b) <em>22 electrons </em>

1s² 2s²2p⁶ 3s²3p⁶ 4s²3d²

There are two electrons in the 4s subshell and two in the 2p subshell. The remaining 18 electrons are in the inner subshells.

(c) <em>17 electrons</em>

1s² 2s²2p⁶ 3s²3p⁵

There are two electrons in the 3s subshell and five in the 2p subshell. The remaining 10 electrons are in the inner subshells.

7 0
3 years ago
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