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3 years ago

What is the quotient of 8.832 x 106 and 9.6 x 102 expressed in scientific notation?

Mathematics

1 answer:

Dvinal [7]3 years ago

6 0

Step-by-step explanation:

$8.832 \times {10}^{6} + 9.6 \times {10}^{2} \\ = 88320 \times {10}^{2} + 9.6 \times {10}^{2} \\ = 88329.6 \times {10}^{2} \\ = 8.83296 \times {10}^{6}$

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A supplier delivers an order for 20 electric toothbrushes to a store. By accident, three of the electric toothbrushes are defect

krek1111 [17]

Answer:

The probability that the first two electric toothbrushes sold are defective is 0.016.

Step-by-step explanation:

The probability of an event, say E occurring is:

$P (E)=\frac{n(E)}{N}$

Here,

n (E) = favorable outcomes

N = total number of outcomes

Let X = number of defective electric toothbrushes sold.

The number of electric toothbrushes that were delivered to a store is, n = 20.

Number of defective electric toothbrushes is, x = 3.

The number of ways to select two toothbrushes to sell from the 20 toothbrushes is:

${20\choose 2}=\frac{20!}{2!(20-2)!}=\frac{20!}{2!\times 18!}=\frac{20\times 19\times 18!}{2!\times 18!}=190$

The number of ways to select two defective toothbrushes to sell from the 3 defective toothbrushes is:

${3\choose 2}=\frac{3!}{2!(3-2)!}=\frac{3!}{2!\times 1!}=3$

Compute the probability that the first two electric toothbrushes sold are defective as follows:

P (Selling 2 defective toothbrushes) = Favorable outcomes ÷ Total no. of outcomes

$=\frac{3}{190}\\$

$=0.01579\\\approx0.016$

Thus, the probability that the first two electric toothbrushes sold are defective is 0.016.

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3 years ago

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vazorg [7]

The answer would be B. linear pair theorem

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Cory earns 52.50 in 7 hours. find the unit rate

faust18 [17]

divide the two:

52.50 / 7 = 7.50 per hour

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2 years ago

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Stolb23 [73]

Answer:

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Step-by-step explanation:

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SSSSS [86.1K]

Answer:

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Step-by-step explanation:

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