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kherson [118]
4 years ago
11

The ratio of two numbers is 5/4 and the first number is 7 more

Mathematics
2 answers:
Makovka662 [10]4 years ago
8 0
I would say 35/28 mabey......
vlada-n [284]4 years ago
4 0
In this case, the numbers would be 5*7 and 4*7 which is 35 and 28 respectively
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When c=3 and d=7<br> 21c + 2d - |-11|d
NeX [460]

Answer:

0

Step-by-step explanation:

21(3) +2(7) - 11(7)             because the absolute value of -11 is 11

63+14-77

=0

8 0
4 years ago
Plz help I have no idea how to answer it​
saveliy_v [14]

5. Answer: see explanation

<u>Step-by-step explanation:</u>

If the roots are m and 3m, then x = m and x = 3m

⇒ x - m = 0    and      x - 3m = 0

⇒ (x - m)(x - 3m) = 0

⇒ x² - 4mx + 3m² = 0

Since x² + px + q = 0   then  p = -4m   and q = 3m²

3p² = 3(-4m)²               16q = 16(3m²)

      = 3(16m²)                      = 48m²

      = 48m²

3p² = 48m² = 16q     ⇒           3p² = 16q

**********************************************************************************************

6. Answer: 8 or 18

<u>Step-by-step explanation:</u>

The Area of the entire rectangle (A = L × w) is 12 × 10 = 120

The Area of the shaded region is 72, so the Area of the non-shaded region is 120 - 72 = 48.

There are two non-shaded triangles.

  • Bigger non-shaded Δ: L = 12-x, w = 10  ⇒ A = \dfrac{10(12-x)}{2}
  • Smaller non-shaded Δ: L = x, w = x ⇒ A=\dfrac{x(x)}{2}

Combine the Areas of both triangles and set it equal to the Area of the non-shaded region:

\dfrac{x(x)}{2}+\dfrac{10(12-x)}{2}=48\\\\\\\dfrac{x^2}{2}+\dfrac{120-10x}{2}=48\\\\\\\dfrac{x^2-10x+120}{2}=48\\\\\\x^2-10x+120=96\\\\x^2-10x+24=0\\\\(x-4)(x-6)=0\\\\x - 4 = 0\quad or\quad x-6=0\\x=4\qquad or\qquad x=6\\\\\text{Based on the image provided, it appears that the x-value will be the}\\\text{smallest of the two possible solutions (4), but both solutions are valid.}

Area of ΔBEF:

\text{when x = 4, A =}\ \dfrac{4(4)}{2}=\dfrac{16}{2}=8\\\\\\\text{when x = 6, A =}\ \dfrac{6(6)}{2}=\dfrac{36}{2}=18

5 0
3 years ago
Tristen walked 13 1/4 hours in May and June. In May he walked 6 4/6 hours. How many hours did he walk inJune
valina [46]

Answer:

6  7/12 hours in June

Step-by-step explanation:

Find the answer to this question by subtracting 6  4/6 hours from the total 13  1/4 hours:

13  1/4 hours   is equivalent to 12  5/4 hours (we borrow '1' from 13  1/4).

Thus, we have

 12  5/4 hours              Note that the LCD of 5/4 and 4/6 is 12.  Thus

-   6  4/6 hours               we have

 12  15/12 hours

-  6    8/12 hours

--------------------------

   6    7/12 hours

Tristen walked 6  7/12 hours in June.

7 0
3 years ago
Can someone help me in this plssss I really need it
kompoz [17]

Answer:

\boxed{-3xy^{2}\sqrt [3] {2x^{2}}}

Step-by-step explanation:

Your expression is

\sqrt [3] {-54x^{5}y^{6}}

Here's how I would simplify it.

\begin{array}{rcll}\sqrt [3] {-54x^{5}y^{6}} & = & \sqrt [3] {(-1)^{3}\times 2 \times 27 \times x^{2} \times x^{3} \times y^{6}} & \text{Factored the cubes}\\& = & \sqrt [3] {(-1)^{3} \times 3^{3}\times x^{3} \times y^{6}\times 2 \times x^{2}} & \text{Grouped the cubes}\\\end{array}

\begin{array}{rcll}& = & \sqrt [3] {(-1)^{3} \times {3^{3}\times x^{3} \times y^{6}}} \times\sqrt [3] { 2 \times x^{2}} & \text{Separated the cubes}\\&=& \mathbf{-3xy^{2}\sqrt [3] {2x^{2}}} & \text{Took cube roots}\\\end{array}

\text{The simplified expression is $\boxed{\mathbf{-3xy^{2}\sqrt [3] {2x^{2}}}}$}

6 0
4 years ago
Find the measure of the arc or angle indicated​
ycow [4]

Step-by-step explanation:

Let O be the center of the circle

We have Angle YOW = 125°

and Angle WOX = 121°.

Therefore Angle YOX = 360° - 125° - 121° = 114°.

(Sum of angles around a point is 360°)

Since Angle at Center = 2 * Angle at Circumference,

Angle YWX

= 0.5 * Angle YOX = 0.5 * 114° = 57°. (A)

6 0
3 years ago
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