Let M = Mary's age.
Let J = Jo's age
Let L = Larry's age.
The sum of their ages is 120. Therefore
M + J + L = 120 (1)
Mary's age is three times Jo's age. Therefore
M = 3J (2)
Larry's age is 5 less than Jo's age. Therefore
L = J - 5 (3)
Substitute (2) and (3) into (1).
3J + J + (J-5) = 120
3J + J + J - 5 = 120
5J - 5 = 120
5J = 120 + 5 = 125
J = 125/5 = 25
Therefore
J = 25, M = 3J = 75, L = J - 5 = 20
Answer: Mary's age = 75; Jo's age = 25; Larry's age = 20
If Mary's age is 75, then Jo's age is 25, and Larry's age is 20.
These problems are solved using the trigonometric function. Trigonometric functions provides the ratio of different sides of a right-angle triangle.
<h3>What are Trigonometric functions?</h3>
The trigonometric function refer to function that are periodic in nature and which lend insight to the relationship between angles and the sides of a triangle that is right angled.
The solutions to x in the respective problems is given as follows:
1st.) x = 5 /Sin(30°)
x = 10
!) sin(45°) = 4/x
x = 4/sin(45°)
x = 4√2
I) Cos(45°) = √3 / x
x = √3 / Cos(45°)
x = √6
E) Tan(60°)
= (3√3) / x
x = (3√3) / 3
W) It is to be noted that for right-triangle that is isosceles in nature, the angle made by the legs and the hypotenuse is always 45°.
x = 45°
N) x² + x² = (7√2)²
x = 7
V) Tan(60°) = 7 / x
x = 7√3/3
K) x² + x² = (9)²
x = 9/√2
Y) Sin(60°) = 7√3/x
x = 14
M) Sin(30°) = x/11
x = 11/2
T) Sin(45°) = x/√10
x = √5
A) x + 2x + 90° = 180°
x = 30°
O) Sin(45°) = √2 / x
x = 2
R) Tan(30°) = x / 4
x = 4/√3
= 4√3 / 3
S) Sin(60°) = x / (10/3)
x = (5√3) / 3
Learn more about Trigonometric functions at:
brainly.com/question/1143565
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Answer:
D
Step-by-step explanation:
3k +4k+2k+10+6
Collect like terms
9k +16
Answred Gauthmath
Answer:
25.4 or 25 times
Step-by-step explanation:
137.25-10.25=127
127/5=25.4