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3 years ago

368 Divided By 216,016

Mathematics

2 answers:

Stels [109]3 years ago

6 0

Answer:

587

Step-by-step explanation:

Okay, so when you divide this using calculator you get your answer

of 587.

But if you would like to do this the right way then it would look something like this:

padilas [110]3 years ago

4 0

0.00170358
is the answer

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PLZ HELP ASAP!!

Lilit [14]

The measure of first angle is 34 degrees and measure of second angle is 56 degrees

Solution:

Given that, the exterior sides of two adjacent angles make a right angle

Therefore, these adjacent angles forms 90 degrees

Let the second angle be "x"

The first angle has a measure that is six more than half the second

Therefore,

first angle = 6 + half of "x"

$\text{ first angle } = 6 + \frac{x}{2}$

Since these two angles forms 90 degrees,

first angle + second angle = 90

$x + 6 + \frac{x}{2} = 90\\\\\frac{2x + 12 + x}{2} = 90\\\\2x + 12+x = 180\\\\3x + 12 = 180\\\\3x = 180 - 12\\\\3x = 168\\\\x = 56$

Therefore, first angle is:

$\rightarrow 6 + \frac{56}{2} = 6 + 28 = 34$

Thus measure of first angle is 34 degrees and measure of second angle is 56 degrees

6 0

3 years ago

How to solve inequalities

sertanlavr [38]

Add or subtract numbers from both sides

4 0

3 years ago

The volume of a rectangular prism is represented by the function x3 + 11x2 + 20x – 32. The width of the box is x – 1 while the h

Oksi-84 [34.3K]

we know that

the volume of a rectangular prism is equal to

$V=L*W*H$

where

L is the length of the box

W is the width of the box

H is is the height of the box

in this problem we have

$V=x^{3\ }+11x^2+20x-32$

$W=x-1$

$H=x+8$

$L=?$

Find the length of the box

Using a graph tool-------> we will determine the roots of the equation of volume

see the attached figure

the roots are

$x=-8\\x=-4\\ x=1$

$x^{3\ }+11x^2+20x-32=(x+8)*(x+4)*(x-1)$

therefore

the answer is

the length of the box is equal to $(x+4)$

8 0

3 years ago

Read 2 more answers

what is the population of the Emperor penguin rounded to the nearest ten thousand and to the nearest hundred thousand

gogolik [260]

Answer:

130,000 to 250,000

Step-by-step explanation:

7 0

3 years ago

Suppose that a function f(x) is defined for all real values of x except at xequals=c. can anything be said about the existence

Margaret [11]

we are given that

f(x) is defined for all values of x except at x=c

Limit may or may not exist

case-1:

If there is hole at x=c , then limit exist

case-2:

If there is vertical asymptote at x=c , then limit does not exist

Examples:

case-1:

$\lim_{x \to c} \frac{x^2-cx}{(x-c)}$

We can simplify it

$\lim_{x \to c} \frac{x(x-c)}{(x-c)}$

$=\lim_{x \to c} x$

$=c$

so, we can see that limit exist and it's value defined

case-2:

$\lim_{x \to c} \frac{1}{(x-c)}$

Left limit is

$\lim_{x \to c-} \frac{1}{(x-c)}$

$=-\infty$

Right Limit is

$\lim_{x \to c+} \frac{1}{(x-c)}$

$=+\infty$

so, we can see that left limit is not equal to right limit

so, limit does not exist

4 0

3 years ago