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STatiana [176]
3 years ago
6

In order to avoid staying after work, a quality control analyst inspects the first 100 items produced that day. Which sampling m

ethod did she use?
systematic
convenience
cluster
stratified
Mathematics
2 answers:
Lemur [1.5K]3 years ago
8 0

Answer: Convenience sampling method.

Step-by-step explanation:

  • A convenience sampling method is one of the main kinds of non-probability sampling methods. It is made up  by researcher according to his or her accessibility  i.e. the researcher select the participants or the items from the population that are easy to reach.

The given statement shows that the quality control analyst inspects the first 100 items produced that day i.e. he selected the items according to his convenience.

mr_godi [17]3 years ago
3 0
Based on the given scenario above wherein the quality control analyst just inspects the first 100 items produced that day in order to avoid staying after work, the sampling method that she used is the CONVENIENCE SAMPLING METHOD. Hope this helps.
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Answer:

It would be the first answer.

Step-by-step explanation:

y=-2x^2+4x-2

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4 0
3 years ago
A cube made out of lead has a mass of 12 grams. A side of the cube has length 1 cm. What would be the mass of the cube whose sid
Ulleksa [173]

Answer:

<h3><em><u>The mass of a lead cube whose </u></em><em><u>side </u></em><em><u>have length 1.5 cm is 40.5 </u></em><em><u>grams</u></em></h3>

Step-by-step explanation:

<u>1. Let's review the information given to</u>

<u>1. Let's review the information given tous to answer the question correctly:</u>

<u>1. Let's review the information given tous to answer the question correctly:Mass of the cube made out of lead</u> = 12

= 12grams

Side of the cube <em>= 1 cm</em>

2. <em><u>What would be the mass of a lead</u></em>

<em><u>What would be the mass of a leadcube whose sides have length 1.5 cm?</u></em>

<em><u>What would be the mass of a leadcube whose sides have length 1.5 cm?For answering the question, let's</u></em>

<em><u>What would be the mass of a leadcube whose sides have length 1.5 cm?For answering the question, let'scalculate the volume of the cube and</u></em>

<em><u>What would be the mass of a leadcube whose sides have length 1.5 cm?For answering the question, let'scalculate the volume of the cube andthen its density, this way:</u></em>

<h3>Volume = Height* Width * Length</h3><h3>Volume=1*1*1</h3><h3>Volume =1 cm</h3>

Let's recall the formula of the density:

Density Mass/Volume, therefore:

Density of the lead <em><u>= 12/1= 12 gr/</u></em><em><u>cm</u></em>

<em><u>Now, let's calculate the volume of the</u></em>

<em><u>Now, let's calculate the volume of thesecond cube:</u></em>

<h3><em>Volume = Height Width Length</em></h3><h3><em>Volume = Height Width LengthVolume 1.5 * 1.5 1.5</em></h3><h3><em>Volume = Height Width LengthVolume 1.5 * 1.5 1.5Volume =3.375 cm3</em></h3>

<u>Finally, let's calculate the mass, using</u>

<u>Finally, let's calculate the mass, usingthe density of the lead we already</u>

<u>Finally, let's calculate the mass, usingthe density of the lead we alreadyknow:</u>

<h3>Density = Mass/Volume</h3><h3><em>12 Mass/3.375</em></h3><h3><em>12 Mass/3.375Mass 12 *3.375</em></h3><h3><em>12 Mass/3.375Mass 12 *3.375Mass = 40.5 gramss</em></h3>
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Step-by-step explanation:

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