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Murrr4er [49]
3 years ago
11

2. (a) A computer can be bought on hire pur-

Mathematics
1 answer:
alexandr1967 [171]3 years ago
6 0

Answer:

b

Step-by-step explanation:

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2х + Зу = -8<br> 2х + Зу = 5<br> Solve and Explain how please
marshall27 [118]

Answer:

my only guess is that if x and y have the same value for both equations it would not make sense if you have the same 2x+3y equal 2 different things

Step-by-step explanation:

thats my guess i hope this helps

6 0
3 years ago
Mary wants to find this product. 58 x 20 How can Mary find the product? A. 0 +16 + 100 B. 0 + 160 + 1000 . C. 58 + 16 + 100 D. 5
Fittoniya [83]

Answer:

B

Step-by-step explanation:

58×20=1160

0+160+1000=1160

8 0
3 years ago
Ava's car used 6 gallons of gas to drive 132 miles. At what rate does her car use gas in gallons per mile? Express your answer i
Sloan [31]

Answer:

1 gallon of gas for 22 miles

Step-by-step explanation:

3 0
3 years ago
Which association best describes the scatter plot?
exis [7]
No association because the dots are just scattered all over the graph

Negative association would be when the dots are going toward downwards

Positive association would be when the dots are going toward upwards
3 0
3 years ago
Find sin(a)&amp;cos(B), tan(a)&amp;cot(B), and sec(a)&amp;csc(B).​
Reil [10]

Answer:

Part A) sin(\alpha)=\frac{4}{7},\ cos(\beta)=\frac{4}{7}

Part B) tan(\alpha)=\frac{4}{\sqrt{33}},\ tan(\beta)=\frac{4}{\sqrt{33}}

Part C) sec(\alpha)=\frac{7}{\sqrt{33}},\ csc(\beta)=\frac{7}{\sqrt{33}}

Step-by-step explanation:

Part A) Find sin(\alpha)\ and\ cos(\beta)

we know that

If two angles are complementary, then the value of sine of one angle is equal to the cosine of the other angle

In this problem

\alpha+\beta=90^o ---> by complementary angles

so

sin(\alpha)=cos(\beta)

Find the value of sin(\alpha) in the right triangle of the figure

sin(\alpha)=\frac{8}{14} ---> opposite side divided by the hypotenuse

simplify

sin(\alpha)=\frac{4}{7}

therefore

sin(\alpha)=\frac{4}{7}

cos(\beta)=\frac{4}{7}

Part B) Find tan(\alpha)\ and\ cot(\beta)

we know that

If two angles are complementary, then the value of tangent of one angle is equal to the cotangent of the other angle

In this problem

\alpha+\beta=90^o ---> by complementary angles

so

tan(\alpha)=cot(\beta)

<em>Find the value of the length side adjacent to the angle alpha</em>

Applying the Pythagorean Theorem

Let

x ----> length side adjacent to angle alpha

14^2=x^2+8^2\\x^2=14^2-8^2\\x^2=132

x=\sqrt{132}\ units

simplify

x=2\sqrt{33}\ units

Find the value of tan(\alpha) in the right triangle of the figure

tan(\alpha)=\frac{8}{2\sqrt{33}} ---> opposite side divided by the adjacent side angle alpha

simplify

tan(\alpha)=\frac{4}{\sqrt{33}}

therefore

tan(\alpha)=\frac{4}{\sqrt{33}}

tan(\beta)=\frac{4}{\sqrt{33}}

Part C) Find sec(\alpha)\ and\ csc(\beta)

we know that

If two angles are complementary, then the value of secant of one angle is equal to the cosecant of the other angle

In this problem

\alpha+\beta=90^o ---> by complementary angles

so

sec(\alpha)=csc(\beta)

Find the value of sec(\alpha) in the right triangle of the figure

sec(\alpha)=\frac{1}{cos(\alpha)}

Find the value of cos(\alpha)

cos(\alpha)=\frac{2\sqrt{33}}{14} ---> adjacent side divided by the hypotenuse

simplify

cos(\alpha)=\frac{\sqrt{33}}{7}

therefore

sec(\alpha)=\frac{7}{\sqrt{33}}

csc(\beta)=\frac{7}{\sqrt{33}}

6 0
3 years ago
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