Answer:
The pressure in that cylinder = 1.12atm
Explanation:
We use general gas law to calculate it. General gas law is gotten by combining Boyle's law, Charles' law and Avogadro's law. Thus
P = nRT/V
Where n = number of moles
R = the gas constant
T is the Temperature, V is the volume and P is the pressure.
Given: T = 319K, V = 24L, R = 0.0821 L.atm/K.mol
The first step is to find n using
n = mass of O2/molar mass of O2
=32.7/32
=1.0219
Now, using P =nRT/V
P = 1.0219 ×0.0821×319÷24
Therefore P = 1.12atm
Answer: 52.5 mL
Hope this helps!
<u>Given:</u>
Volume of the unknown monoprotic acid (HA) = 25 ml
<u>To determine: </u>
The concentration of the acid HA
<u>Explanation:</u>
The titration reaction can be represented as-
HA + NaOH → Na⁺A⁻ + H₂O
As per stoichiometry: 1 mole of HA reacts with 1 mole of NaOH
At equivalence point-
moles of HA = moles of NaOH
For a known concentration and volume of added NaOH we have:
moles of NaOH = M(NaOH) * V(NaOH)
Thus, the concentration of the unknown 25 ml (0.025 L) of HA would be-
Molarity of HA = moles of HA/Vol of HA
Molarity of HA = M(NaOH)*V(NaOH)/0.025 L
