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3 years ago

What items are true about a block of ice at -10°C as you continue to apply heat

Chemistry

1 answer:

zhenek [66]3 years ago

5 0

1. its temperature will rise continuously until it melts

I don't believe that any of the other answers are correct because it can not stay at a certain temperature if it is melting

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A solution is 40 cetic acid by mass. the density of this solution is 1.049 g/ml. Calculate the mass of pure acetic acid in 220 m

taurus [48]

The mass of pure acetic acid in 220 ml of the given solution at 20°C is 92.311 g

<h3>What is Acetic acid?</h3>

Acetic acid is a type of carboxylic acid and also known as ethanoic acid

Its formula is CH₃COOH.

It is an organic compound and is a colorless liquid

It is mostly used in the production of vinegar

40 % acetic acid by mass means,

40 g of acetic acid is dissolved in 100 g of solution.

The density of solution at 20°C,

$\rho = 1.049 g/ml$

We know,

$\rho = \frac{m}{V}$

$V = \frac{m}{\rho}$

The volume of the solution, $V = \frac{100}{1.049}$ = 95.33 ml

95.33 ml of solution contains 40 g of pure Acetic acid

220 ml of solution contains $\frac{40 \times 220}{95.33}$ = 92.311 g of pure Acetic acid

Thus, the mass of pure Acetic acid in 220 ml of solution at 20°C is 92.311 g

Learn more about acetic acid:

brainly.com/question/24304533

#SPJ4

7 0

2 years ago

A perfect cube of aluminum metal was found to weigh 20.00 g. The density of aluminum is 2.7 g/ml. What are the dimensions of the

denis23 [38]

Answer:

Height = 1.9493 cm

Width = 1.9493 cm

Depth = 1.9493 cm

Solution:

Data Given:

Mass = 20 g

Density = 2.7 g/mL

Step 1: Calculate the Volume,

As,

Density = Mass ÷ Volume

Or,

Volume = Mass ÷ Density

Putting values,

Volume = 20 g ÷ 2.7 g/mL

Volume = 7.407 mL or 7.407 cm³

Step 2: Calculate Dimensions of the Cube:

As we know,

Volume = length × width × depth

So, we will take the cube root of 7.407 cm³ which is 1.9493 cm.

Hence,

Volume = 1.9493 cm × 1.9493 cm × 1.9493 cm

Volume = 7.407 cm³

4 0

3 years ago

Consider the following balanced reaction. How many grams of water are required to form 75.9 g of HNO3? Assume that there is exce

Iteru [2.4K]

Answer:

10.85 g of water

Explanation:

First we write the balanced chemical equation

$3NO_{2} +H_{2}O -->2HNO_{3} +NO$

Then we calculate the number of moles of nitric acid produced

n(HNO3) = $\frac{mass}{molar mass} =\frac{75.9g}{63.02g/mol}=1.2044 mol$

According to the balanced equation, water needed in moles is always half the number of moles of HNO3 produced. So since we will produce 1.2044 mol of HNO3, we will need 0.6022 mol of water. Now to calculate what mass that is:

mass(water)=number of moles*molar mass=0.6022mol*18.02g/mol=10.85g

5 0

3 years ago

Can someone please help me? :(

Dmitriy789 [7]

Answer:

Trade winds

Explanation:

I am not sure

7 0

2 years ago

Help please<br>........

IgorLugansk [536]

I am pretty sure it is Vitamin A... but I could be wrong. Sorry if it is wrong.

3 0

3 years ago