The pH of the solution of the given acid is 3.099
Let HX be the weak acid:
HX ⇌ 
+ 
For which:
= [ ][ ] / [HX]
If lies in the range 
we can assume that the equilibrium concentrations used in the expression are a good enough approximation to the initial concentrations.
Rearranging and taking negative logs of both sides gives:
pH = ![\frac{1}{2} [pK_{a} - loga]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%5BpK_%7Ba%7D%20-%20loga%5D)
a is the concentration of the acid.
= -log (2×
) = 5.69
pH = ![\frac{1}{2} [5.69- (-0.508)]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%5B5.69-%20%28-0.508%29%5D)
pH = 3.099
Learn more about pH of acid here;
brainly.com/question/13043236
#SPJ4
Answer:
is the mole fraction of potassium dichromate.
Explanation:
Mass of potassium dichromate = 24.42 g
Moles of potassium dichromate =
Mass of water = 240.0 g
Moles of water =
Mole fraction is calculated by:
is the mole fraction of potassium dichromate.
Well, in an atom, there are an equal number of protons and electrons so they cancel each other out.
