A student compares the boiling point of substances having different intermolecular forces. <u>Boiling points of various substances</u> is the dependent variable that student most likely use.
<h3>Does the nature of intermolecular forces present in different substance affect their boiling points?</h3>
The boiling point of a substance is proportional to the strength of its intermolecular forces, the higher the boiling point, the stronger the intermolecular forces. We can compare the strengths of intermolecular forces by comparing the boiling points of different substances.
<h3>What properties are affected by intermolecular forces?</h3>
Intermolecular forces are measured by boiling points.
Intermolecular forces increase as bond polarization increases.
Ionic > hydrogen bonding > dipole dipole > dispersion is the order of the strength of intermolecular forces (and thus their impact on boiling points).
<h3>How can you determine strong and weak intermolecular forces?</h3>
Substances with strong intermolecular forces are very attracted to one another and are held together tightly. These substances require a great deal of energy to separate, whereas substances with weak intermolecular forces are held together very loosely and have weak interactions.
Learn more about intermolecular forces:
<u><em>brainly.com/question/13479228</em></u>
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3.18 grams of product (Cu I) - 2.54 grams of Cu (reactant) = .64 grams of Sulfur, by law of conservation of mass.
The answer is C.
While the Hydrogen atom symbol itself is labeled with 3, it is being multiplied by the coefficient of 3, giving us a total of 9 atoms.
Answer:
they must know the fountion of the equipment
Explanation:
because without knowing the fountion of the equipment, you will always get a wrong or a different conclusion
The average atomic mass of Jz is 331.3 u.
The average atomic mass of Jz is the <em>weighted average</em> of the atomic masses of its isotopes.
We multiply the atomic mass of each isotope by a number representing its <em>relative importance</em> (i.e., its fractional abundance).
Thus,
⅗ × 329.1 u = 197.46 u
⅖ × 334.5 u = <u>133.80 u</u>
TOTAL = 331.3 u
