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Bingel [31]
4 years ago
15

Consider the quadratic equation y^2-y=6. what is the error with the solution below?

Mathematics
1 answer:
erica [24]4 years ago
5 0

Answer:

y=-2 or y=3

Step-by-step explanation:

Y^2-y-6=0

y^2-3y+2y-6=0

y(y-3)+2(y-3)=0

(y+2)(y-3)=0

y=-2 or y=3

hope it helps

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Sketch the algebra-tile shape at right on your paper. Write an expression for the
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Answer:

Part 1) P=(4x+4)\ units

Part 2)

a) P=32\ units

b) P=26\ units

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Step-by-step explanation:

<u><em>The complete question in the attached figure</em></u>

Part 1) Write an expression for the  perimeter of the shape

we know that

The figure is composed by a larger square, a rectangle and a smaller square

1) The area of the larger square is given

A=x^2\ units^2

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A=x\ units^2

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3) The length and the width of the smaller square is x units

see the attached figure N 2 to better understand the problem

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P=(x+x+x+x+1+1+1+1)

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(3<em>x</em>⁴ - 8<em>x</em>³ - <em>x</em>² + 9<em>x</em> + 5) - (3<em>x</em>⁴ - 6<em>x</em>³) = -2<em>x</em>³ - <em>x</em>² + 9<em>x</em> + 5

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8 0
4 years ago
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