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3 years ago

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The Green Goober, a wildly unpopular superhero, mixes 33 3 3 liters of yellow paint with 55 5 5 liters of blue paint to make 88

8 8 liters of special green paint for his costume.

1 answer:

Lera25 [3.4K]3 years ago

5 0

Check picture ................ z z z z

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Which graph represents y=3(x-3)^2+3

tensa zangetsu [6.8K]

Graph y = (–5/3)x – 2.

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3 years ago

A phase modulator produces a maximum phase shift of 45 degrees. The modulation frequency range is 300 to 4000 Hz. What is the ma

sergejj [24]

Answer:

Maximum frequency deviation is 2616.29509 Hz

Maximum frequency deviation=(4000-3000)cos45

Max frequency deviation=2616.29509 Hz

8 0

3 years ago

creating a diagram so far this session a team has won 51 out of 68 games identify the value of a b c and d that complete the bar

Flauer [41]

Answer:

a = 25

b = 100

c = 17

d = 68

Step-by-step explanation:

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3 years ago

Is anyone taking saxon Advanced mathematics?

vivado [14]

Not me...........................

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3 years ago

PLEASE HELP ME GUYS OR I WONT PASS <br>this calculus!!!!

KonstantinChe [14]

Answer:

b. $\displaystyle \frac{1}{2}$

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Algebra I</u>

Functions
Function Notation
Exponential Rule [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$
Exponential Rule [Root Rewrite]: $\displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}$ <u> </u>

<u>Calculus</u>

Derivatives

Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]: $\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

<em /> $\displaystyle H(x) = \sqrt[3]{F(x)}$ <em />

<em />

<u>Step 2: Differentiate</u>

Rewrite function [Exponential Rule - Root Rewrite]: $\displaystyle H(x) = [F(x)]^\bigg{\frac{1}{3}}$
Chain Rule: $\displaystyle H'(x) = \frac{d}{dx} \bigg[ [F(x)]^\bigg{\frac{1}{3}} \bigg] \cdot \frac{d}{dx}[F(x)]$
Basic Power Rule: $\displaystyle H'(x) = \frac{1}{3}[F(x)]^\bigg{\frac{1}{3} - 1} \cdot F'(x)$
Simplify: $\displaystyle H'(x) = \frac{F'(x)}{3}[F(x)]^\bigg{\frac{-2}{3}}$
Rewrite [Exponential Rule - Rewrite]: $\displaystyle H'(x) = \frac{F'(x)}{3[F(x)]^\bigg{\frac{2}{3}}}$

<u>Step 3: Evaluate</u>

Substitute in <em>x</em> [Derivative]: $\displaystyle H'(5) = \frac{F'(5)}{3[F(5)]^\bigg{\frac{2}{3}}}$
Substitute in function values: $\displaystyle H'(5) = \frac{6}{3(8)^\bigg{\frac{2}{3}}}$
Exponents: $\displaystyle H'(5) = \frac{6}{3(4)}$
Multiply: $\displaystyle H'(5) = \frac{6}{12}$
Simplify: $\displaystyle H'(5) = \frac{1}{2}$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Derivatives

Book: College Calculus 10e

5 0

3 years ago