Question

A bat crashes into the vertical front of an accelerating subway train. If the coefficient of static friction between bat and train is 0.860, what is the minimum acceleration of the train that will allow the bat to remain in place (without sliding down)?

Answer 1

Answer:

The minimum acceleration will be $11.40m/sec^2$                          

Explanation:

We have given that coefficient of static friction $\mu _s=0.860$

Frictional force is given by $F=\mu_s N=\mu _sma$

Weight is given by $W=mg$

For train to allow the bat to remain in place $mg=\mu _sma$

$a=\frac{g}{\mu _s}=\frac{9.81}{0.860}=11.40m/sec^2$

So the minimum acceleration will be $11.40m/sec^2$