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docker41 [41]
3 years ago
11

Dose poop smell good

Physics
2 answers:
Eduardwww [97]3 years ago
4 0
No, of course not. it it’s waste leaving your body.
mixer [17]3 years ago
3 0

Explanation:fniowovwvtfoyyosb

gmmme points also the answer that was here befor me was funny

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Suppose that instead of being inclined to Earth's orbit around the Sun, the Moon’s orbit was in the same plane as Earth’s orbit
d1i1m1o1n [39]

Answer:

12

Explanation:

A solar eclipse occurs when the moon in between the sun and the earth. Since in reality, the moons orbit is inclined, this aligning doesnt occur often. But if the orbit of the moon were in the same plane as the earth orbit, and since the moon orbits the earth once a month, the three objects would align every month. This makes it 12 times in a year.

8 0
3 years ago
Why does nobody like me?
timurjin [86]
That is the wrong attiude!....dipwad.
3 0
3 years ago
Read 2 more answers
When air pressure decreases, the mercury in a barometer _____.
siniylev [52]

Answer:

The mercury in the barometer will go down as there is less air pressing down on the bulb of the barometer to push mercury up.

Explanation:

7 0
3 years ago
What is the smallest time interval in which a 5.7 T magnetic field can be turned on or off if the induced emf around the patient
VLD [36.1K]

The smallest time interval in which the magnetic field can be turned on or off to induced the emf is 47.5 s.

<h3>Emf induced in the coil</h3>

The emf induced in the coil is calculated as follows;

emf = dФ/dt

where;

  • dФ is change in flux
  • dt is change in time

0.12 = 5.7/dt

dt = 5.7/0.12

dt = 47.5 s

Thus, the smallest time interval in which the magnetic field can be turned on or off to induced the emf is 47.5 s.

Learn more about emf here: brainly.com/question/13744192

#SPJ11

3 0
2 years ago
The stone, which weighs 400 g, is thrown upwards at a speed of 20 m / s. Climbed to a height of 12 m. Determine: what is equal t
maxonik [38]

Given that,

Mass of the stone, m = 400 g = 0.4 kg

Initial speed, u = 20 m/s

It is climbed to a height of 12 m.

To find,

The work done by the resistance force.

Solution,

Let v is the final speed. It can be calculated by using the conservation of energy.

v=\sqrt{2gh} \\\\v=\sqrt{2\times 9.8\times 12} \\\\v=15.33\ m/s

Work done is equal to the change in kinetic energy. It can be given as follows :

W=\dfrac{1}{2}m(v^2-u^2)\\\\=\dfrac{1}{2}\times 0.4\times (15.33^2-20^2)\\\\=-32.99\ J

So, the required work done is 32.99 J.

3 0
3 years ago
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