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Leto [7]
3 years ago
11

1. 7(6-(-4)) What is this I don’t know

Mathematics
2 answers:
Makovka662 [10]3 years ago
7 0

Answer:

70

Step-by-step explanation:

1 you take the parenthese off 6 minus -4 which equals 10 bc when you subtract a negative form a positve it adds them together so now you have 10 then you would do 10 multilied by 7 bc the 7 is outside of the parentheses so you divide and you get your answer which is 70

Marina CMI [18]3 years ago
5 0
So you would start with removing the parentheses so 6- - 4 would be 6+4 because the double negative and then that would be 10 so 7 times 10 so your answer is 70
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10. Simplify the rational expression by rationalizing the denominator. 3 sqrt 160/sqrt 1350x A) 2 sqrt 15x/15x B) 3 sqrt 160/135
Viefleur [7K]
The simplified expression by rationalizing the denominator is (C)\frac{4 \sqrt{15x} }{15x}.

First we must simplify the expression:
\frac{3 \sqrt{160} }{\sqrt{1350x} } =  \frac{12 \sqrt{10} }{15 \sqrt{6x} } =  \frac{4 \sqrt{10} }{5 \sqrt{6x} }

Then we factor the rational parts and cancel it out:
\frac{4 \sqrt{2} \sqrt{5} }{5 \sqrt{2} \sqrt{3x} } = \frac{4\sqrt{5} }{5\sqrt{3x} }

Then we rationalize the expression:
\frac{4\sqrt{5} }{5\sqrt{3x} } * \frac{\sqrt{3x} }{\sqrt{3x} } = \frac{4 \sqrt{15x} }{5*3x} = \frac{4 \sqrt{15x} }{15x}

<span>Finally, the simplified expression by rationalizing the denominator is (C)\frac{4 \sqrt{15x} }{15x}.</span>
7 0
3 years ago
Write the letters of the expressions that are equivalent to the given expression.
Tresset [83]

Answer: A.) 10x + 15

Step-by-step explanation:

You would distribute (multiply) the 5 to the 2x which would then make it 10x and you would distribute (multiply) the 5 to the 3 which would then make it 15. Because the 5 is a positive number the sign stays the same.

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3 0
3 years ago
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patriot [66]

Answer:

\frac{1}{7}-3(\frac{3}{7}n-\frac{2}{7})=1-\frac{9}{7}n

Step-by-step explanation:

Given : Expression \frac{1}{7}-3(\frac{3}{7}n-\frac{2}{7})

To find : Combine like terms to create an equivalent expression ?

Solution :

Step 1 - Write the expression,

\frac{1}{7}-3(\frac{3}{7}n-\frac{2}{7})

Step 2 - Apply distributive property, a(b+c)=ab+ac

=\frac{1}{7}-3\times \frac{3}{7}n+3\times \frac{2}{7}

=\frac{1}{7}-\frac{9}{7}n+\frac{6}{7}

Step 3 - Combine like terms,

=\frac{1}{7}+\frac{6}{7}-\frac{9}{7}n

=\frac{1+6}{7}-\frac{9}{7}n

=\frac{7}{7}-\frac{9}{7}n

=1-\frac{9}{7}n

Therefore,  \frac{1}{7}-3(\frac{3}{7}n-\frac{2}{7})=1-\frac{9}{7}n

4 0
3 years ago
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erastova [34]
Decimal: 3.14

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7 0
3 years ago
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-Dominant- [34]

Answer:

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Step-by-step explanation:

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6 0
2 years ago
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