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vova2212 [387]
3 years ago
7

At which of the given values is the graph discontinuous?

Mathematics
1 answer:
hammer [34]3 years ago
8 0

Answer: Option d.

Step-by-step explanation:

You can solve the problem shown above keeping on mind the facts shown below:

Observe that there is a point in the graph in which there is a jump or a discontinuity between both parts of the function.

The point mentioned is at x=5

By definition, this indicates that the function shown is not continuous at that point.

Therefore, you can conclude that the value in which the graph is discontinuous is the value of the option d: 5

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Suppose that P(n) is a propositional function. Determine for which improper subset of the domain of n the statement P(n) must be
Alinara [238K]

Answer:

a) P(n) is true for all 'n' in the set ; { 0,2,4,6,8 ….. }

b) P(n) is true for all 'n' in the set ; { 0,1,2,3,4,5 ............ }

Step-by-step explanation:

a) As P(0) is true

we will assume that

  • P(2) is true
  • P(4) is true
  • P(6) is true

this simply means  that ;  P(n) is true for all 'n' in the set

{ 0,2,4,6,8 ….. }

b) since P(0) and P(1) are true

we will assume that

  • P( 0+2 ) = P(2)  is true

also P(1) and P(2) are true

we will assume that

  • P(1+2) = P(3)  is true

Also from the previous answers it can be seen that P(2) + P(3) is true

we will assume

  • P(2+2) = P(4)  is true

This simply means that P(n) is true for all 'n' in the set

{ 0,1,2,3,4,5 ............ }

8 0
3 years ago
Can someone pls help me
erica [24]

I would love to help you :)

So what do we know?:

We know that side A has a length of 25, and side B has a length of 21.

So that leaves us to find the length of side C correct?

Answer

Tbh I'm to lazy to explain how I got this and its mostly likely incorrect. but I think the answer is

4

(most likely incorrect LOL)

<u><em>IM SO SORRY IF I MADE YOU FAIL THE QUESTION SDNFKJSDFSDF</em></u>

5 0
2 years ago
Read 2 more answers
Which of these statements is true for f(x)=(1/10)^x
lana66690 [7]

Step-by-step explanation:

Considering the function

f\left(x\right)=\:\left(\frac{1}{10}\right)^x

Analyzing option A)

Considering the function

f\left(x\right)=\:\left(\frac{1}{10}\right)^x

Putting x = 1 in the function

f\left(1\right)=\:\left(\frac{1}{10}\right)^1

f\left(1\right)=\:\left\frac{1}{10}\right

So, it is TRUE that when  x = 1 then the out put will be f\left(1\right)=\:\left\frac{1}{10}\right

Therefore, the statement that '' The graph contains \left(1,\:\frac{1}{10}\right)  '' is TRUE.

Analyzing option B)

Considering the function

f\left(x\right)=\:\left(\frac{1}{10}\right)^x

The range of the function is the set of values of the dependent variable for which a function is defined.

\mathrm{The\:range\:of\:an\:exponential\:function\:of\:the\:form}\:c\cdot \:n^{ax+b}+k\:\mathrm{is}\:\:f\left(x\right)>k

k=0

f\left(x\right)>0

Thus,

\mathrm{Range\:of\:}\left(\frac{1}{10}\right)^x:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)>0\:\\ \:\mathrm{Interval\:Notation:}&\:\left(0,\:\infty \:\right)\end{bmatrix}

Therefore, the statement that ''The range of f(x) is y > \frac{1}{10} " is FALSE

Analyzing option C)

Considering the function

f\left(x\right)=\:\left(\frac{1}{10}\right)^x

The domain of the function is the set of input values which the function is real and defined.

As the function has no undefined points nor domain constraints.

So, the domain is -\infty \:

Thus,

\mathrm{Domain\:of\:}\:\left(\frac{1}{10}\right)^x\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:

Therefore, the statement that ''The domain of f(x) is x>0 '' is FALSE.

Analyzing option D)

Considering the function

f\left(x\right)=\:\left(\frac{1}{10}\right)^x

As the base of the exponential function is less then 1.

i.e. 0 < b < 1

Thus, the function is decreasing

Also check the graph of the function below, which shows that the function is decreasing.

Therefore, the statement '' It is always increasing '' is FALSE.

Keywords: function, exponential function, increasing function, decreasing function, domain, range

Learn more about exponential function from brainly.com/question/13657083

#learnwithBrainly

3 0
3 years ago
Read 2 more answers
Can someone please explain to me how to find the interquartile range of something?
Alika [10]
I’ll do an example you have the numbers 1,5,7,2,9 you can tell the median is 7 right? So go from the very left and the median (7) and do the same thing you do to find median. (Id recommend crossing the numbers off as you go if that makes sense! :)
3 0
3 years ago
The accompanying data on x = current density (mA/cm2) and y = rate of deposition (m/min)μ appeared in a recent study.
gtnhenbr [62]

Answer:

a) r=\frac{4(333)-(200)(5.37)}{\sqrt{[4(12000) -(200)^2][4(9.3501) -(5.37)^2]}}=0.9857  

The correlation coefficient for this case is very near to 1 so then we can ensure that we have linear correlation between the two variables

b) m=\frac{64.5}{2000}=0.03225  

Now we can find the means for x and y like this:  

\bar x= \frac{\sum x_i}{n}=\frac{200}{4}=50  

\bar y= \frac{\sum y_i}{n}=\frac{5.37}{4}=1.3425  

b=\bar y -m \bar x=1.3425-(0.03225*50)=-0.27  

So the line would be given by:  

y=0.3225 x -0.27  

Step-by-step explanation:

Part a

The correlation coeffcient is given by this formula:

r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}  

For our case we have this:

n=4 \sum x = 200, \sum y = 5.37, \sum xy = 333, \sum x^2 =12000, \sum y^2 =9.3501  

r=\frac{4(333)-(200)(5.37)}{\sqrt{[4(12000) -(200)^2][4(9.3501) -(5.37)^2]}}=0.9857  

The correlation coefficient for this case is very near to 1 so then we can ensure that we have linear correlation between the two variables

Part b

m=\frac{S_{xy}}{S_{xx}}  

Where:  

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}  

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}  

With these we can find the sums:  

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=12000-\frac{200^2}{4}=2000  

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i){n}}=333-\frac{200*5.37}{4}=64.5  

And the slope would be:  

m=\frac{64.5}{2000}=0.03225  

Now we can find the means for x and y like this:  

\bar x= \frac{\sum x_i}{n}=\frac{200}{4}=50  

\bar y= \frac{\sum y_i}{n}=\frac{5.37}{4}=1.3425  

And we can find the intercept using this:  

b=\bar y -m \bar x=1.3425-(0.03225*50)=-0.27  

So the line would be given by:  

y=0.3225 x -0.27  

4 0
3 years ago
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