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vova2212 [387]
3 years ago
7

At which of the given values is the graph discontinuous?

Mathematics
1 answer:
hammer [34]3 years ago
8 0

Answer: Option d.

Step-by-step explanation:

You can solve the problem shown above keeping on mind the facts shown below:

Observe that there is a point in the graph in which there is a jump or a discontinuity between both parts of the function.

The point mentioned is at x=5

By definition, this indicates that the function shown is not continuous at that point.

Therefore, you can conclude that the value in which the graph is discontinuous is the value of the option d: 5

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A deep sea driver descended from a rock with an elevation of -45.5 feet to a coral reef with an elevation of -88.5 feet. How far
vlada-n [284]

Answer:

43 feet

Step-by-step explanation:

How far is referring to the distance between the two numbers given.

In general, the distance between two numbers, a and b,

is given by |b-a| .

You have that you are finding the distance between -45.5 ft and -88.5 ft.

So the distance between those numbers is given by:

|-45.5-(-88.5)|

|-45.5+88.5|

|88.5-45.5|

|43.0|

|43|  

43      (Since the number inside the | | has a distance of 43 from 0)

The distance between -45.5 ft and -88.5 ft is 43 ft.

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3 years ago
Hunter took out a $3,500 loan with interest to pay for some business supplies. He will repay the loan in 3 years with monthly pa
sleet_krkn [62]

Answer:

A

Step-by-step explanation:

4 0
2 years ago
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The amount of calories consumed by customers at the Chinese buffet is normally distributed with mean 2885 and standard deviation
aliina [53]

Answer:

a.  X~N(2,885, 651)

b.  0.086291

c.  0.00058

d.  3213.10 calories

Step-by-step explanation:

a. -A normal distribution is expressed in the form X~N(mean, standard deviation).

-Let X a random variable denoting  the number of calories consumed.

-X is a is a normally distributed random variable with mean 2885 and standard deviation 651.

-This distribution is expressed as X~N(2,885, 651)

b. The probability that less than 2000 calories are consumed is calculated using the formula:

P(X

#substitute the given values in the formula to solve for P:

P(X

Hence, the probability of consuming less than 2000 calories is 0.08691

c. The proportion of customers consuming more than 5000 calories is calculated as:

P(X>x)=P(z>\frac{\bar X-\mu}{\sigma})\\\\=P(Z>\frac{5000-2885}{651})\\\\=P(z>3.2488)\\\\=1-0.99942\\\\=0.00058

Hence, the proportion of customers consuming over  5000 calories is 0.00058

d. The least amount of calories to get the award is calculated as:

1% is equivalent to a z value of 0.50399.

-We equate this to the formula to solve for the mean consumption:

0.01=P(z>\frac{\bar X-\mu}{\sigma})\\\\=P(z>\frac{\bar X-2885}{651})\\\\\1\%=0.50399 \\\\\frac{\bar X-2885}{651}=0.50399 \\\\\bar X=0.50399\times 651+2885\\\\=3213.09

Hence, the least amount of calories consumed to qualify for the award is 3213.10 calories.

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Answer:

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